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eduard
2 years ago
13

WHAT IS THE CHEMICAL NAME FOR ALKYNE HAVING

Chemistry
1 answer:
madreJ [45]2 years ago
4 0

Answer:

Ee your house 6r2f5r56rrrr6gjyf

Explanation:

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1.
kenny6666 [7]

<u>Answer:</u> The value of K_p is 324

<u>Explanation:</u>

We are given:

Initial pressure of S_8(g) = 1.00 atm

The chemical equation for the conversion of S_8(g) to S_2(g) follows:

                  S_8(g)\rightleftharpoons 4S_2(g)

<u>Initial:</u>          1

<u>At eqllm:</u>    1-x       4x

We are given:

Equilibrium partial pressure of S_8(g)=0.25atm

Evaluating the value of 'x', we get:

\Rightarrow (1-x)=0.25\\\\\Rightarrow x=1-0.25=0.75

The expression of K_p for the above reaction follows:

K_p=\frac{(p_{S_2})^4}{p_{S_8}}

p_{S_2}=4x=(4\times 0.75)=3atm

p_{S_8}=0.25atm

Putting values in above expression, we get:

K_p=\frac{3^4}{0.25}\\\\K_p=324

Hence, the value of K_p is 324

5 0
3 years ago
If the standard solutions had unknowingly been made up to be 0.0024 m agno3 and 0.0040 m k2cro4, would this have affected your r
Mnenie [13.5K]
2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Hence by mixing 0.0024M AgNO3 and 0.004M
K2CrO4, we will have Ag2CrO4 which is precipitated out and leave us with 
0.0024M KN03 which is mixed with (0.004-0.0024/2)M, it can be 0.0028M, of K2Cr04
6 0
3 years ago
Read 2 more answers
How many moles of NaOH are present in 25.0 mL of a 0.1000 M NaOH solution?
Kisachek [45]
25 * 10^-3 L * 0.1 Mole/L = 25*10^-4 Moles

Hope it helps.
4 0
3 years ago
Read 2 more answers
Describe how you would separate rock salt to obtain salt crystals and pure dry sand.
USPshnik [31]

Answer:

Separating Sand and Salt

Probably the easiest method to separate the two substances is to dissolve salt in water, pour the liquid away from the sand, and then evaporate the water to recover the salt.

6 0
3 years ago
Read 2 more answers
If you were in a completely dark room, the room would still be "shining" in this type of light:
Vsevolod [243]
C)infrared is the answer 
3 0
3 years ago
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