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Alekssandra [29.7K]
3 years ago
15

Resistance and resistivity are related by a:

Physics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

<u>At a given temperature</u>

Resistivity depends only on the material and resistance depends on resisitvity, length of the wire and cross-sectional area of the wire

Explanation:

At a given temperature the resistance of a specimen with unit length and unit cross sectional area is called resisitivity.

We get

        R = ρl/A

where; R = resistance

            ρ = resistivity

            l = length of the wire

            A = cross-sectional area of the wire

So you get, ρ ∝ 1\l

                   ρ ∝ A

                   ρ ∝ R

                   

You might be interested in
Which of the following can easily be studied objectively? history meteorology sociology theology
Vilka [71]
<h2>Answer: meteorology </h2>

Explanation:

From the given options , meteorology is the only one that can be studied objectively, since it is an interdisciplinary science that relies on basic sciences such as physics and mathematics and applied sciences to the study of the atmosphere, the weather, the phenomena produced and the physical laws that govern it. In addition, meteorology uses objective techniques to study and predict the various phenomena that occur in the atmosphere.

Unlike history, sociology and theology, in which there is a possibility of the existence of some data are subjective and not true or only based on opinions <u>without scientific evidence</u>.

8 0
3 years ago
A brick lands 10.1 m from the base of a building. If it was given an initial velocity of 8.6 m/s [61º above the horizontal], how
Montano1993 [528]
<h2>Answer: 10.52m</h2><h2 />

First, we have to establish the <u>reference system</u>. Let's assume that the building is on the negative y-axis and that the brick was thrown at the origin (see figure attached).

According to this, the initial velocity V_{o} has two components, because the brick was thrown at an angle \alpha=61\º:

V_{ox}=V_{o}cos\alpha   (1)

V_{ox}=8.6\frac{m}{s}cos(61\º)=4.169\frac{m}{s}  (2)

V_{oy}=V_{o}sin\alpha   (3)

V_{oy}=8.6\frac{m}{s}sin(61\º)=7.521\frac{m}{s}   (4)

As this is a projectile motion, we have two principal equations related:

<h2>In the x-axis: </h2>

X=V_{ox}.t  (5)

Where:

X=10.1m is the distance where the brick landed

t is the time in seconds

If we already know X and V_{ox}, we have to find the time (we will need it for the following equation):

t= \frac{X}{ V_{ox}}  (6)

t=2.42s  (7)

<h2>In the y-axis: </h2>

-y=V_{oy}.t+\frac{1}{2}g.t^{2}   (8)

Where:

y is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>

g=-9.8\frac{m}{s^{2}} is the acceleration due gravity

Substituting the known values, including the time we found on equation (7) in equation (8), we will find the height of the building:

-y=(7.521\frac{m}{s})(2.42s)+\frac{1}{2}(-9.8\frac{m}{s^{2}}).(2.42s)^{2}   (9)

-y=-10.52m   (10)

Multiplying by -1 each side of the equation:

y=10.52m >>>>This is the height of the building

3 0
3 years ago
a constant current of 3 a for 4 hours is required to charge an automotive battery.if the terminal voltage is 10 t/2 v, where t i
Korvikt [17]

The charge transported as a result of charging is 43200C .

we can note the following data from the statement :

Current (i) = 3A

Time interval (t) = 4 hrs = 14400secs

As we know ,

Current is defined as the rate of flow of the charges between two points when a potential difference is applied between them.

Mathematically , it can be written as

Current(i) = charge (q)/ time(t)

Q = i × t

   = 3 × 14400

   = 43200 C

By dividing the value of the current passed through the circuit by the time for which the charge is passed gives out the value of the charge passed .

learn more on charges :

brainly.com/question/15238352

#SPJ4

3 0
1 year ago
A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I
Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

E=-\dfrac{d\phi}{dt}

E=-B\dfrac{dA}{dt}

E=-B\dfrac{A_{2}-A_{1}}{dt}

E=B\dfrac{A_{1}-A_{2}}{dt}.....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

l=2\times 2\pi\times r_{1}

l=2\times 2\pi\times 0.63

l=7.916\ m

The length when wire is in one loop

l=2\pi\times r_{2}

7.916=2\times \pi\times r_{2}

r_{2}=\dfrac{7.916}{2\times \pi}

r_{2}=1.259\ m

We need to calculate the initial area

A_{1}=N\times\pi\times r_{1}^2

Put the value into the formula

A_{1}=2\times3.14\times(0.63)^2

A_{1}=2.49\ m^2

The final area is

A_{2}=N\times\pi\times r_{2}^2

A_{2}=1\times\pi\times(1.259)^2

A_{2}=4.98\ m^2

Put the value of initial area and final area in the equation (I)

E=0.219\dfrac{2.49-4.98}{0.0572}

E=-9.533\ V

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0
3 years ago
Helpppppppppppppppp its timeddddddddddd
leva [86]

Answer:

<u>The answer is the third option.</u>

Explanation:

The electrostatic force, Coulomb's force, is a force that depends on the inverse of the square distance, it is a non-contact force.

On the other hand, stretched spring is a contact force, it needs a contact external force.

Therefore, <u>the answer is the third option.</u>

I hope it helps you!

4 0
3 years ago
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