Answer:
Explanation:
The change is as follows
P₁ V₁ to 3P₁, V₁ ( constt volume ) --- first process
3P₁,V₁ to 3P₁ , 5V₁ ( constt pressure ) ---- second process
In the first process Temperature must have been increased 3 times . So if initial temperature is T₁ then final temperature will be 3 T₁
P₁V₁ = n R T₁ , n is no of moles of gas enclosed.
nRT₁ = P₁V₁
Heat added at constant volume = n Cv ( 3T₁ - T₁)
= n x 5/3 R X 2T₁ ( for diatomic gas Cv = 5/3 R)
= 10/3 x nRT₁
= 10/3x P₁V₁
In the second process, Temperature must have been increased 5 times . So if initial temperature is 3T₁ then final temperature will be 15 T₁
Heat added at constant pressure in second case
= n Cp ( 15T₁ - 3T₁)
= n x 7/3 R X 12T₁ ( For diatomic gas Cp = 7/3 R)
= 28 x nRT₁
= 28 P₁V₁
Answer:
1525 meters above ground
Explanation:
So to do this you will need to write this in slope intercept form or 
. So 650 would be the b, 175 would be the m, and the x would be 5 so the equation would be 
so if you solve or simplify the equation you will get 1525 meters above the ground and that would be our final answer.
<span>When a seed or plant is said to be inactive, it is dormant. Dormancy occurs when <span>a plant reduces its metabolic activity.</span></span>
The force ffrom the ground that holds the rock up and prevents her from falling through the gound, unless the ground breaks.
Answer:
the diameter of the second pipe is 2.52 in
Explanation:
Given the data in the question;
We know that; the rate of flow is the same;
so
Av1 = Av2
v ∝ √h
= 
= √( 
)
( π/4.D1² / π/4.D2² ) = √( )
( D1² / D2² ) = √( 
) since second is double of first
so
( D1² / D2² ) = √( 
)
3² / D2² = √2
D2²√2 = 9
D2² = 9/√2
D2² = 9 / 1.4142
D2² = 6.364
D2 = √ 6.364
D2 = 2.52 in
Therefore, the diameter of the second pipe is 2.52 in
