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Stolb23 [73]
3 years ago
9

Kinetic energy can be calculated using the formula KE = 1/2mv2. What is the kinetic energy of a bicycle that has a mass of 20 kg

and is traveling at a velocity of 10 m/sec?​
Physics
1 answer:
Alenkasestr [34]3 years ago
8 0
<h3>Answer:</h3>

KE = 1000 J

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Physics</u>

<u>Energy</u>

Kinetic Energy Formula: \displaystyle KE = \frac{1}{2}mv^2

  • Energy is in Joules
  • m is mass (in kg)
  • v is velocity (in m/s)
<h3>Explanation:</h3>

<u>Step 1: Define</u>

m = 20 kg

v = 10 m/s

<u>Step 2: Find KE</u>

  1. Substitute [KE]:                    \displaystyle KE = \frac{1}{2}(20)(10)^2
  2. Exponents:                          \displaystyle KE = \frac{1}{2}(20)(100)
  3. Multiply:                               \displaystyle KE = (10)(100)
  4. Multiply:                               \displaystyle KE = 1000
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<h3>What is temperature?</h3>

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A 7g block of ice was added to a coffee cup full of 103.4 grams of water. The water had an initial temperature T₁ = 24.5 C and a final temperature T₂ = 19.2 C after all the ice had melted.

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Qgain = ms(T₂ -T₁ )

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Qgain = 0.1034 x 4.18 x (24.5 - 19.2)

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Argon gas enters steadily an adiabatic turbine at 900 kPa and 450C with a velocity of 80 m/s and leaves at 150 kPa with a veloc
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Answer:

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Explanation:

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as

v_{1}=\frac{RT_{1}}{P_{1}}=\frac{0.2081\times723}{900}=0.1672m^{3}/kg

m_{f}=\frac{1}{v_{1}}\times A_{1}V_{1} = \frac{1}{0.1672}\times(0.006)(80)=2.871kg/sec

for Ideal gasses, the enthalpy change can be calculated using the formula

h_{2}-h_{1}=C_{p}(T_{2}-T_{1})

hence we have

W_{out}= -m_{f}((C_{p}(T_{2}-T_{1}) + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})

250= -2.871((0.5203(T_{2}-450) + \frac{150^{2}}{2\times 1000} - \frac{80^{2}}{2\times 1000})

<em>Note: to convert the Kinetic energy term to kilojoules, it was multiplied by 1000</em>

evaluating the above equation, we have T_{2}=267.3C

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5 0
3 years ago
A human being can be electrocuted if a current as small as 51.0 ma passes near the heart. an electrician working with sweaty han
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The fatal current is 51 mA = 0.051 Ampere.

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==================

This is what the arithmetic says IF the information in the question
is correct.

I don't know how true this is, and I certainly don't plan to test it,
but I have read that a current as small as  15 mA  through the
heart can be fatal, not  51 mA .

If 15 mA can do it, and the sweaty electrician's resistance is
really 2,050 Ω, then the fatal voltage could be as little as  31 volts !

The voltage at the wall-outlets in your house is  120 volts in the USA !
THAT's why you don't want to stick paper clips or a screwdriver into
outlets, and why you want to cover unused outlets with plastic plugs
if there are babies crawling around.
6 0
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