Expansion work against constant external pressure: w=-pex Δ Δ V 3. The attempt at a solution . I tried following that. Because Vf>>Vi, and Vf=nRT/pex, then w=-pex x nRT/pex=-nRT (im assuming n is number of moles of CO2?). 1 mole of CaCO3 makes 1 mole of CO2, so plugging in numbers, I get 8.9kJ, although I dont use the 1 atm pressure at all
Answer:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Explanation:
Answer:
a
The x- and y-components of the total force exerted is

b
The magnitude of the force is

The direction of the force is
Clockwise from x-axis
Explanation:
From the question we are told that
The magnitude of the first charge is 
The magnitude of the second charge is 
The position of the second charge from the first one is 
The magnitude of the third charge is 
The position of the third charge from the first one is 


The position of the third charge from the second one is



The force acting on the third charge due to the first and second charge is mathematically represented as

Substituting values



The magnitude of
is mathematically evaluated as

The direction is obtained as

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Speed = Distance/Time. So you are required to know A. Distance and period of time