HELPPPPPURGENT PLEASE NB 35

You walk exactly 250 steps North, turn around, and then walk exactly 400 steps South. How far are you from your starting

german

Answer:

150 steps south

Explanation:

250 north 250 back to start then continue south for remainder of 400 steps. 150 south

3 0

2 years ago

Which of the following is an example of a physical change?

Stels [109]

Answer:

1 question is- I believe 4. Melting Question 2 is Density

Explanation:

THOUGHT ABOUT IT!!!

7 0

3 years ago

A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall

dolphi86 [110]

Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

Explanation:

(a) The work done by the force P on the box is given by the following formula:

$W_P=Px$

P: applied force = 171N

x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

$W_P=(171N)(8.80m)=1504.8J$

(b) The work don by the friction force is:

$W_f=F_fx=\mu N x=\mu Mg x$

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J$

(c) The Normal force is

$N=Mg=(46.0kg)(9,8m/s^2)=450.8N$

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

$W_N=0J$

(d) the same as before:

$W_g=0J$

8 0

2 years ago

During a workout, the football players at State U ran up the stadium stairs in 61 s. The stairs are 130 m long and inclined at a

NeTakaya

Answer:

P = 1097 Watt

Explanation:

given,

length of stairs, L = 130 m

inclination with horizontal,θ = 30°

mass of the football player = 105 Kg

time = 61 s

we know,

$Power = \dfrac{work}{time}$

Work = change in Potential energy

h = L sin 30°

h = 130 x 0.5

h = 65 m

W = m g h

W = 105 x 9.8 x 65

W = 66885 J

now,

$P = \dfrac{66885}{61}$

P = 1097 Watt

hence, the power output on the way is 1097 W

5 0

2 years ago

Inductors in series. Two inductors L1 = 1.05 H and L2 = 2.07 H are connected in series and are separated by a large distance so

hodyreva [135]

The inductance of several inductors in series is the sum of all the individuals ... just like for resistors.

a). With 1.05H and 2.07H in series, the equivalent total inductance is <em>3.12H</em> , provided the inductors can't influence each other with their magnetic fields.

b). If you had 30 identical inductors in series, each with inductance of 3.03H, AND none of them could influence any other ones with their magnetic fields, their combined equivalent inductance would be

(30) · (3.03H) = <em>90.9 H</em> .

4 0

3 years ago