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ira [324]
3 years ago
8

"on a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. wh

en max pulls on the sled with 12 n of force, directed at an angle of 15° above the ground, how much work does max do on the sled as he pulls his sister 25 m in the snow?"

Physics
1 answer:
devlian [24]3 years ago
3 0
Refer to the diagram shown below.

The angle θ = 15° relative to the direction of motion.
Therefore the force acting in the direction of motion is
(12 N) cos(15°) = 11.59 N

By definition,
Work = Force x Distance.
Therefore work done in moving the sled by 25 m is
Work = (11.59 N)*(25 m) = 289.8 J

Answer: 289.8 J

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Re-arranging the equation to have the value of the gravity,

\frac{N_v(y)}{n_0} = e^{-\frac{mghy}{KbT}}

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ln(\frac{0.3n_0}{n_0}) = -\frac{mgy}{KbT}

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g = -\frac{(1.38*10^{-23}J/K)(20K)(Ln(0.3))}{10^{-19}(3*10^{-2})}

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g = 0.1m/s^2

Therefore the correct answer is C.

4 0
4 years ago
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Answer:

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