Distance = (15 minutes) x (60 sec/min) x (2 meter/sec)
Distance = (15 x 60 x 2) (minute-sec-meter / min-sec)
Distance = <em>1,800 meters </em>
<span>λν=c
(wavelength x frequency = speed)
speed = 45 x 0.1
= 4.5 m/s</span>
Answer:
Part a)

Part b)

Explanation:
As we know that electric force on electric charge is given as

here we have

E = 153 N/C
now force is given as

Gravitational force on electric charge near surface of earth is given as


now the ratio of two forces is given as


Part b)
Now the ball is balanced by the electric force and the force of gravity on it
so here we have



here we have

Explanation:
Given that,
Initial speed of the bag, u = 7.3 m/s
Height above ground, s = 24 m
We need to find the speed of the bag just before it reaches the ground. It can be calculated using third equation of motion as :


v = 22.88 m/s
So, the speed of the bag just before it reaches the ground is 22.38 m/s. Hence, this is the required solution.