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maw [93]
3 years ago
5

An airplane, starting from rest, moves down the runway at constant acceleration for 18 s and then takes off at a speed of 60 m/s

. What is the average acceleration of the plane?
Physics
2 answers:
ruslelena [56]3 years ago
4 0

Answer:

a =3.33 m/s²

Explanation:

given,

initial speed of Plane, u = 0 m/s

final speed of plane, v = 60 m/s

time of the acceleration, t = 18 s

average acceleration of the plane, a = ?

average acceleration is equal to change in velocity per unit time.

a = \dfrac{v - u}{t}

a = \dfrac{60 - 0}{18}

a = \dfrac{60}{18}

     a =3.33 m/s²

Hence, average acceleration of the plane is equal to a =3.33 m/s²

ElenaW [278]3 years ago
3 0

Answer:

Explanation:

Given

Airplane runs for a time period of t=18\ s

Airplane takes off with a velocity of v=60\ m/s

It is given that airplane starts from rest i.e. initial velocity u=0

acceleration is the rate of change of velocity thus it is given by

a=\frac{v-u}{t}

a=\frac{60-0}{18}

a=3.33\ m/s^2

Average acceleration for 18 s is 3.33 m/s^2    

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