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Sonja [21]
4 years ago
13

____________ is the activity performed prior to participating in an activity.

Physics
2 answers:
disa [49]4 years ago
8 0
I think its B but it could also be D because usually they say line up and than u do the activity or strech so..



Plz mark as brainlist hope i helped
dem82 [27]4 years ago
5 0
B, warm up makes most sense
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a stone is dropped from a bridge and hits the pavement below in 2 seconds. what is the velocity of the stone when it hits the pa
ira [324]
Well gravity is 9.8m/s so i would assume 19.6m/2 is the velocity
8 0
3 years ago
Read 2 more answers
in a situation to choose energy respurces between hydroelectric power and thermal power, what would be your choice? give reasons
DaniilM [7]

Answer:

Hydroelectric power

Explanation:

The Hydroelectric power is more green than the thermal power. It will not give out the smoke that thermal power will

6 0
3 years ago
El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La
allsm [11]

Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta

En donde:

\omega_{f}: es la velocidad angular final =  2000 rpm = 209,4 rad/s

\omega_{0}: es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.  

Resolviendo la ecuación (1) para α, tenemos:

\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}  

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.  

b) El tiempo transcurrido se puede encontrar como sigue:

\omega_{f} = \omega_{0} + \alpha t

Resolviendo para t, tenemos:

t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

3 0
3 years ago
Please help with last equation i don't understand at all!!!
GalinKa [24]
What equation?
please comment on this and type it in
5 0
3 years ago
Find the required answer to the following by substituting the numbers. (Bonus points for knowing the units). PLEASE ANSWER
Alex73 [517]

Answer:

a) F=ma

F=13.2×10

F=132

b) I=P/V

I=75/15

I=5

4 0
3 years ago
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