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djverab [1.8K]
3 years ago
6

How do i solve x² + x - 2

Mathematics
1 answer:
jeka943 years ago
8 0
Square x first then add x then subtract by 2
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A person bikes 2
Lerok [7]

Answer:

The person bikes 20 miles in an hour

Step-by-step explanation:

5 0
2 years ago
The quotient of the opposite of a number squared and three
Mars2501 [29]

Answer:

"The quotient of the opposite of a number squared and 3"  

Take "the opposite of a number squared" and call it y.  

So you get "The quotient of y and 3"  

This is y/3.  

Now what is y? "The opposite of a number squared"  

Take "The opposite of a number" and call it z.  

So y is "z squared"  

Replacing y, we get z^2 / 3  

But what is z? "The opposite of a number"  

Call "a number" x.  

The opposite of x is -x.  

So z is "-x"  

Replacing z, we get (-x)^2 / 3



8 0
3 years ago
Lian needs to solve the quadratic equation: x^2 - 4x - 2 = 0. Which statement about how Lian should solve this equation is true?
Ulleksa [173]

Answer:

x = 4.45 or x = - 4.45

Step-by-step explanation:

Here are the steps:

Substitute the values,

4+\sqrt{-4^2-4(1*-2)} ÷ 2 × 1

x = 2 ± √6

x = 4.45 or x = - 4.45

<em>good luck, i hope this helps :)</em>

5 0
3 years ago
Read 2 more answers
How would you write 2.11 as a fraction in simplest form
Anni [7]
So,

2.11 can be written as 2 and 11 hundredths, or 2 \frac{11}{100} .

2 \frac{11}{100}   is in simplest form.
4 0
3 years ago
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
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