You want to use PEMDAS for this.
<em>P</em>= arenthesis ( )
<em>E</em>= xponents a²
<em>M</em>= ultiply ×
<em>D</em>= ivide ÷
<em>A</em>= dd +
<em>S</em>= ubtract -
What you want to do is go in order and ask yourself as you go.
Are there any <u><em>Parenthesis</em></u>? <em>No
</em>Are there any <u><em>Exponents</em></u><em />? <em>No</em>
Is there any <em /><u><em>Multiplication</em></u><em />? <em>Yes
</em><em />Is there any <em><u>Division</u></em>? <em>No
</em><em />Is there any <em><u>Addition</u></em>? <em>No
</em><em />Is there any <em><u>Subtraction</u></em><u />? <em>Yes</em><em>
</em><em />Thats when you stop and you multiply what you have in the PEMDAS. Top to bottom. 3x5 which gives you 15. Now you equation is 45-15. Thats when you subtract and you get your answer which is 30.
A
using the Cosine rule in ΔSTU
let t = SU, s = TU and u = ST, then
t² = u² + s² - (2us cos T )
substitute the appropriate values into the formula
t² = 5² + 9² - (2 × 5 × 9 × cos68° )
= 25 + 81 - 90cos68°
= 106 - 33.71 = 72.29
⇒ t = 
≈ 8.5 in → A
Answer:
15.9
Step-by-step explanation:
the answer in standard form is 10+3
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
