If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
1 answer:
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Answer:
Explanation:
60000 kJ / h = 60000 x 1000 / (60 x 60 )
= 16667 J /s
a)
where and
are heat supplied and heat given from outside source .
Here = 16667 J/s
= 15.684
16667 / W = 15.684
W= minimum power supplied = 1062.7 W.
b )
If
=19.87
= 838.8 W .
Answer:
its surface temperature = 54.84 ° C
Explanation:
The density of aluminium = 2700 kg/m ³
Heat capacity = 897 J/Kg.K
radius of the sphere (r) = 0.081029 m
= 25 °C
= 124.978 °C
time (t) = 767.276 s
Using the formula :
where.
Replacing our values ;we have:
T ≅ 54.84 ° C
Therefore, its surface temperature = 54.84 ° C