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amid [387]
3 years ago
8

A traveling electromagnetic wave in a vacuum has an electric field amplitude of 50.9 V/m. Calculate the intensity ???? of this w

ave. Then, determine the amount of energy ???? that flows through area of 0.0277 m2 over an interval of 11.9 s , assuming that the area is perpendicular to the direction of wave propagation.
Physics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

3.44 W/m²

1.134 J

Explanation:

E₀ = Intensity of electric field = 50.9 V/m

I = Intensity of electromagnetic wave

Intensity of electromagnetic wave is given as

I = (0.5) ε₀ E₀² c

I = (0.5) (8.85 x 10⁻¹²) (50.9)² (3 x 10⁸)

I = 3.44 W/m²

A = Area = 0.0277 m²

t = time interval = 11.9 s

Amount of energy is given as

U = I A t

U = (3.44) (0.0277) (11.9)

U = 1.134 J

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What is true about the velocity of sound waves in solids compared to air?
ivolga24 [154]
<h2>The correct option is (A)</h2>

Explanation:

Travels faster in solids because the particles are closer together.

The reason for the above statement is -

(i) Sound waves travel through the medium (solid, Liquid, and gas), more denser is the medium more is the speed of sound.

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4 0
3 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
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859.07 N

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F=ma\\\Rightarrow F=870\times -10.93\\\Rightarrow F=859.07\ N

The magnitude of the average force on the bumper is 859.07 N

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