Which expression describes the third vector in the diagram, which leads from the tip of B to the tip of Ā?

A confined aquifer with a porosity of 0.15 is 30 m thick. The potentiometric surface elevation at two observation wells 1000 m a

AlekseyPX

Answer:

Part (a) The flow rate per unit width of the aquifer is 1.0875 m³/day

Part (b) The specific discharge of the flow is 0.0363 m/day

Part (c) The average linear velocity of the flow is 0.242 m/day

Part (d) The time taken for a tracer to travel the distance between the observation wells is 4132.23 days = 99173.52 hours

Explanation:

Part (a) the flow rate per unit width of the aquifer

From Darcy's law;

$q = -Kb\frac{dh}{dl}$

where;

q is the flow rate

K is the permeability or conductivity of the aquifer = 25 m/day

b is the aquifer thickness

dh is the change in th vertical hight = 50.9m - 52.35m = -1.45 m

dl is the change in the horizontal hight = 1000 m

q = -(25*30)*(-1.45/1000)

q = 1.0875 m³/day

Part (b) the specific discharge of the flow

$V = \frac{Q}{A} = \frac{q}{b} = -K\frac{dh}{dl}\\\\V = -(25 m/d).(\frac{-1.45 m}{1000 m}) = 0.0363 m/day$

V = 0.0363 m/day

Part (c) the average linear velocity of the flow assuming steady unidirectional flow

Va = V/Φ

Φ is the porosity = 0.15

Va = 0.0363 / 0.15

Va = 0.242 m/day

Part (d) the time taken for a tracer to travel the distance between the observation wells

The distance between the two wells = 1000 m

average linear velocity = 0.242 m/day

Time = distance / speed

Time = (1000 m) / (0.242 m/day)

Time = 4132.23 days

$= 4132.23 days *\frac{24 .hrs}{1.day} = 99173.52, hours$

4 0

3 years ago

The front and rear sprockets on a bicycle have radii of 8.40 and 4.91 cm, respectively. The angular speed of the front sprocket

Rudik [331]

Explanation:

It is given that,

Radius of the front sprockets, $r_f=8.4\ cm=0.084\ m$

Radius of the rear sprockets, $r_r=4.91\ cm=0.0491\ m$

The angular speed of the front sprocket is 12.3 rad/s, $\omega_f=12.3\ rad/s$

(a) Linear speed of the front sprockets, $v_f=r_f\times \omega$

$v_f=0.084\times 12.3$

$v_f=1.0332\ m/s$

$v_f=103.32\ cm/s$

Linear speed of the rear sprockets, $v_r=r_r\times \omega$

$v_r=0.0491\times 12.3$

$v_r=0.60393\ m/s$

$v_r=60.393\ cm/s$

(b) Let $a_r$ is the centripetal acceleration of the chain as it passes around the rear sprocket.

$a_r=\dfrac{v_r^2}{r_r}$

$a_r=\dfrac{(60.393)^2}{0.0491}$

$a_r=74283.39\ m/s^2$

$a_r=7428339\ cm/s^2$

`Hence, this is the required solution.

8 0

3 years ago

Read 2 more answers

During the day, susan notices that the wind is blowing onshore at the beach. What is this called? land breeze land breeze sea br

In-s [12.5K]

The correct option is (b) Sea breeze

During the day, susan notices that the wind is blowing onshore at the beach called sea breeze.

What is sea breeze?

Any wind that flows from a big body of water onto or onto a landmass is called a sea breeze or an onshore breeze.
Sea breezes form as a result of changes in air pressure brought on by the different heat capacities of water and dry land. Sea breezes are therefore more confined than prevailing winds.
A sea wind is frequently seen along coasts after sunrise because land warms up far more quickly than water does when exposed to solar radiation.
The sea wind front is significant because it can serve as a catalyst for afternoon thunderstorms and provide welcome cooling along the coast.

Learn more about the sea breeze with the help of the given link:

brainly.com/question/13015619

#SPJ4

8 0

2 years ago

A glider of mass 5.0 kg hits the end of a horizontal rail and bounces off with the same speed, in the opposite direction. The co

NeTakaya

To solve the exercise it is necessary to apply the concepts given in Newton's second law and the equations of motion description.

Let's start by defining acceleration based on speed and time, that is

$a = \frac{v}{t}$