Answer:
1. 142.1 GPa
2. 98.52%
Explanation:
1. The modulus of elasticity of carbon-epoxy composite is calculated using the following formula:
Ec = VmEm + VfEf
where Vm: volume of Epoxy
Em: modulus of the elasticity of the epoxy
Vf: volume of carbon fiber
Ef: modulus of the elasticity of the carbon fiber
Given that :
Vm = 0.6
Em = 3.5 GPa
Vf = 0.4
Ef: 350 Gpa
Therefore Ec = (0.6 × 3.5 GPa + (0.4 × 350 GPa)
Ec = 142.1 GPa
The modulus of elasticity of carbon-epoxy composite is 142.1 GPa
2. Percentage of load carried by the carbon fibers is given by the following equation: Ff/Fc = (Ef/Ec)×Vf
where Ff is the force carried by carbon fibers, Fc is the force applied to the composite, Ec is the modulus of elasticity of the composite, Ef is the modulus of the elasticity of the carbon fiber and Vf the volume of carbon fiber.
Given that:
EF = 350 Gpa
Ec = 142.1 GPa
Vf = 0.4
Substituting the above values into the equation:
Ff/Fc = (350 GPa/142.1 GPa)×0.4 = 0.9852 = 98.52%
The percentage of load carried by the carbon fibers is there 98.52%
Answer:
See attachment for complete answer.
Explanation:
Given that:Suppose that all the dislocations in 2000 mm3 of crystal were somehow removed and linked end to end. Given 1 m =0.0006214 mile, how far (in miles) would this chain extend for dislocation densities of
(a) 103 mm-2 (undeformed metal)
(b) 1010 mm-2 (cold-worked metal)
See attchment for completed solvings
Answer:
a) see attachment
b) A= m0m1+ m1m2+ m0m2
see attachment for K-map
c) see attachment
Explanation:
a) see attachment for truth table
b) see attachment for k-map
A= m0m1+ m1m2+ m0m2
c) see attachment for gate level circuit
19 vans are needed. 9 for the boys and 10 for the girls
If you only can have 8 students in each van you need to divide each number by 8. So 72/8 is 9 for the boys and 75/8 is 9.4 since this is over 9 you’ll need 10 for the girls.