All categories

4 years ago

What is the probability that someone in the survey considered reading books or surf the internet as the best entertainment?

Mathematics

2 answers:

Elis [28]4 years ago

5 0

Answer:

Answer is $\frac{31}{100}$

Step-by-step explanation:

values given in table

Reading books percentage is 22

hence we can write probability as

Probability (reading books) = $\frac{22}{100}$

percentage of surfing internet is= 9

Probability of surfing internet is = $\frac{09}{100}$

the probability (reading books or surf the internet)= P(reading books) + P(surf the internet)

probability (reading or surf)= $\frac{22}{100}$ + $\frac{09}{100}$

= $\frac{31}{100}$

mr Goodwill [35]4 years ago

3 0

Answer:

31/100

Step-by-step explanation:

From the given table

Reading books percentage is 22

so Probability (reading books) = $\frac{22}{100}$

Surf the internet percentage is 9

Probability (surf the internet) = $\frac{9}{100}$

the probability (reading books or surf the internet)= P(reading books) + P(surf the internet)

probability (reading or surf)= $\frac{22}{100} +\frac{9}{100}$

= $\frac{31}{100}$

You might be interested in

find 65÷4.write your answer using a remainder ,a fraction and a decimal. then tell which form of the answer you prefer .explain

antiseptic1488 [7]

65/4 = (Decimal) 16.25 (Fraction) 16 1/4
The choice I prefer to use is fraction. It is easier to work with, in my opinion, when it comes to multiplying or dividing with other numbers/fractions.

5 0

3 years ago

Read 2 more answers

How do you do this question?

Andrei [34K]

Answer:

Solution : Option B, or 9π

Step-by-step explanation:

We are given that y = x, x = 3, and y = 0.

Now assume we have a circle that models the given information. The radius will be x, so to determine the area of that circle we have πx². And knowing that x = 3 and y = 0, we have the following integral:

$\int _0^3$

So our set up for solving this problem, would be such:

$\int _0^3x^2\pi \:$

By solving this integral we receive our solution:

$\int _0^3x^2\pi dx,\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> \pi \cdot \int _0^3x^2dx\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1}\\=> \pi \left[\frac{x^{2+1}}{2+1}\right]^3_0\\=> \pi \left[\frac{x^3}{3}\right]^3_0\\\mathrm{Compute\:the\:boundaries}: \left[\frac{x^3}{3}\right]^3_0=9\\\mathrm{Substitute:9\pi }$