Question

Find the zeros of the polynomial function        f(x) = x2 – 12x + 20

Answer 1

${f(x) = x^2 - 12x + 20 = x^2-2x-10x+20 = x(x-2)-10(x-2) = (x-2)(x-10)}$

f(x)=0

$(x-2)(x-10)=0$

$x-2=0 \ or \ x-10=0$

$x=2 \ or \ x=10$