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LuckyWell [14K]
3 years ago
8

I understand this and i need to show work please someone explain

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

Height: 8.471

Volume: 2245.641cm3

Step-by-step explanation:

To solve this problem we need to find the volume of the cone, then the volume of the semi sphere, and then, sum all together.

To obtain the volume of the cone, we need to focus our attention in the triangle that already was given to us, since its height is the same as the height of the cone.

We can use the tan(26,7) since it relates the radius of the cone, and its height.

This gives us. h=9/tan(27,9)= 8.471 cm

The volume of the cone is then. 718.629cm3

The volume of the spehere is 1527.012 cm3

FInally the volumen of the toy is the sum of both volumes previously obtained:

2245.641cm3.

Refer the attached picture for a more detailed procedure.

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the answer is 8.45

Step-by-step explanation:

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(2^4x+4)÷(2^x+1)<br> 60 POINTS<br> BRANLIEST IF RIGHT
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Answer:

\frac{2^4^x + 4}{2^x + 1}

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2 years ago
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The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high,
Andrej [43]

Answer:

A. $18

B. $200

C. p\in (16,20)

Step-by-step explanation:

Function:

f(p) = -50p^2 + 1,800p - 16,000

<u>Parts A and B:</u>

The price that generates the maximum profit is ate vertex of parabola. Find the coordinates of the vertex:

p_v=\dfrac{-b}{2a}=\dfrac{-1,800}{2\cdot (-50)}=\dfrac{1,800}{100}=18\\ \\f(p_v)=-50\cdot 18^2+1,800\cdot 18-16,000=200

The price that generates the maximum profit is $18

The maximum profit is $200

<u>Part C:</u>

The company breaks even when the profit is positive. From the graph of the function you can see that the graph of the function is over p-axis for all p\in (16,20), so the positive profit is for p\in (16,20)

In p=16 and p=20, the profit is 0 and when p<16 and p>20, there will be a loss.

7 0
4 years ago
∫∫(x+y)dxdy ,d là miền giới hạn bởi x²+y²=1
igor_vitrenko [27]

It looks like you want to compute the double integral

\displaystyle \iint_D (x+y) \,\mathrm dx\,\mathrm dy

over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.

Convert to polar coordinates, in which <em>D</em> is given by the set

<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}

and

<em>x</em> = <em>r</em> cos(<em>θ</em>)

<em>y</em> = <em>r</em> sin(<em>θ</em>)

d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>

Then the integral is

\displaystyle \iint_D (x+y)\,\mathrm dx\,\mathrm dy = \iint_D r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \int_0^{2\pi} \int_0^1 r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \underbrace{\left( \int_0^{2\pi}(\cos(\theta)+\sin(\theta))\,\mathrm d\theta \right)}_{\int = 0} \left( \int_0^1 r^2\,\mathrm dr \right) = \boxed{0}

3 0
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Round to the nearest tenth 1.763
Vilka [71]
1.8 is the answer rounded
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3 years ago
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