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dezoksy [38]
3 years ago
15

Please help with this problem. Thank you.​

Physics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:

Explanation:

F = mω²R

F = 15(2π/8.5)²(7.8)

F = 63.93044788...

F = 63.9 N

answer a) is the closest. No idea how they got a value that low unless they used a poor approximation for π.

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What is the magnitude of the velocity when the elastic potential energy is equal to the kinetic energy? (Assume that U=0 at equi
zhannawk [14.2K]

Answer:

Explanation:

General Equation of SHM is given by

x=A\cos \omega t

v=-A\omega \sin \omega t

where x=position of particle

A=maximum Amplitude

\omega =angular frequency

t=time

At any time Total Energy is the sum of kinetic Energy and Elastic potential Energy i.e. \frac{1}{2}kA^2

where k=spring constant

Potential Energy is given by U=\frac{1}{2}kx^2

also it is given that Potential Energy(U) is equal to Kinetic Energy(K)

Total Energy=K+U

Total=2U=2\times \frac{1}{2}kx^2

\frac{1}{2}kA^2=2\times \frac{1}{2}kx^2

x=\pm \frac{A}{\sqrt{2}}

at x=\frac{A}{\sqrt{2}}

velocity is v=\frac{A\omega}{\sqrt{2}}

6 0
3 years ago
What two factors affect the strength of a magnetic field
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Answer:

Factors Affecting the Strength of the Magnetic Field of an Electromagnet: Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core.

Explanation:

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7 0
3 years ago
A planet outside of our solar system
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Answer:

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4 0
3 years ago
A ball is attached to one end of a wire, the other end being fastened to the ceiling. The wire is held horizontal, and the ball
Aleksandr [31]

Answer:

the velocity (magnitude and direction) of the ball)  just before the collision is v_i = 5.144 \ m/s

The  velocity (magnitude and direction) of the ball)  just after  the collision is v_f = - 1.129  \ m/s

Explanation:

According to the law of conservation of energy;

m__{ball}} gh = \frac{1}{2}m__{ball}}v_i^2\\\\2* m__{ball}} gh = m__{ball}}v_i^2\\\\v_i^2 = \frac{2*m_{ball}gh}{m_{ball}}\\\\v_i^2 = 2gh\\\\v_i = \sqrt{2gh} \\\\v_i = \sqrt{2*9.8*1.35}\\\\

v_i = 5.144 \ m/s

Thus; the velocity (magnitude and direction) of the ball)  just before the collision is v_i = 5.144 \ m/s

Since, Air resistance is negligible, and the collision is elastic.

The equation for the conservation of momentum and energy can be expressed as:

v_f = [\frac{m_1 -m_2}{m_1+m_2}]v_i\\\\v_f =  [\frac{m_{ball} -m_{block}}{m_{ball}+m_{block}}]v_i\\\\v_f = [\frac{1.6 -2.5}{1.6+2.5}]*5.144\\\\

v_f = - 1.129  \ m/s

The  velocity (magnitude and direction) of the ball)  just after  the collision is v_f = - 1.129  \ m/s

8 0
2 years ago
Ariel and Jackson are playing miniature golf. Ariel's ball rolls into a long, straight upward incline with a speed of 3.054 m/s
Salsk061 [2.6K]

Answer:

The length is s =  3.73 \ m

Explanation:

From the question we are told that

  The speed is  v  =  3.054 \  m/s

  The acceleration a =  -0.7762  m/s^2

   The time taken is  t =  1.51 \ s

     

Generally from kinematics equation the length of the inclined plane is mathematically represented as

         s =ut + \frac{1}{2} * at^2

=>      s = 3.054 *1.51  + \frac{1}{2} * (-0.7762) *(1.51)^2

=>   s =  3.73 \ m

8 0
3 years ago
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