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siniylev [52]
3 years ago
6

Use Newton's laws to explain why a falling object dropped from a 57m tower accelerates initially but then reaches constant veloc

ity. Discuss the forces acting on the object
Physics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

At the point of dropping the object, by Newton's first law due to gravitational force F_g = m × g, accelerates

By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)

As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.

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Susan works in the research and development department. She has recently purchased a large high-speed external drive and has att
ivann1987 [24]

     The reason why Susan's drive is not working is that she has connected the drive to a USB 2.0 port, which does not have enough power for her drive.

<h3>What is the USB?</h3>

USB is a short acronym for the original word called a Universal Serial Bus. USB is a connector interface for connecting a computer to peripherals and other devices.

USB comes in different specs such as the:

  • USB 2.0
  • USB 3.0

Some of the characteristics differences between USB 2.0 and 3.0 are:

A USB 2.0 requires 480 Mbps for data transfer speed while USB 3.0 requires 4800 Mbps.

A USB 2.0 has the ability to use a maximum power of 500 mA, while USB 3.0 can make use of up to 900 mA.

From the given information, It is stated that the drive requires a minimum of 400 Mbps and at least 900 mA;

Therefore, it implies that the drive is supposed to work with a power of at least 900 mA for it to work.

But since it is not working, we can conclude that the drive is connected to a USB 2.0 port (500 mA) which does not have enough power for the drive.

Learn more about the USB port here:

brainly.com/question/13714615

5 0
2 years ago
The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, what should be the focal length an
yuradex [85]

Answer:

The focal length of the appropriate corrective lens is 35.71 cm.

The power of the appropriate corrective lens is 0.028 D.

Explanation:

The expression for the lens formula is as follows;

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

Here, f is the focal length, u is the object distance and v is the image distance.

It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.

Put v= -71.4 cm and u= 24.0 cm in the above expression.

\frac{1}{f}=\frac{1}{24}+\frac{1}{-71.4}

\frac{1}{f}=0.028

f= 35.71 cm

Therefore, the focal length of the corrective lens is 35.71 cm.

The expression for the power of the lens is as follows;

p=\frac{1}{f}

Here, p is the power of the lens.

Put f= 35.71 cm.

p=\frac{1}{35.71}

p=0.028 D

Therefore, the power of the corrective lens is 0.028 D.

3 0
3 years ago
A system proposed by the U.S. Navy for underwater submarine communication, called ELF (for extremely low frequency), operates wi
kow [346]

Answer

Wavelength= 30*20^8/30=10^7m

Explanation:

Velocity = frequency *wavelength

We're frequency=30HZ

Velocity of light= 3*10^8m/s

Wavelength= 30*20^8/30=10^7m

Explanation:

7 0
3 years ago
Read 2 more answers
Which of the following is a heterogeneous mixture?
Reil [10]
That would be Italian dressing because it does not mix completely therefore it is the definition of a heterogeneous mixture
8 0
3 years ago
A 100-n force has a horizontal component of 80 n and a vertical component of 60 n. the force is applied to a box which rests on
iragen [17]
<span>160 Joules

   For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance: 80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.

   So the cart has a final kinetic energy of 160 Joules.</span>
6 0
3 years ago
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