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Zinaida [17]
3 years ago
10

Is the Florida scrub a forest or grassland

Physics
1 answer:
PIT_PIT [208]3 years ago
4 0
It is a forest. Hope this helps. Much luck
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Which factors affect gravitational force? Check all that apply.
alina1380 [7]

Answer:

distance between the objects

masses of the objects

Explanation:

Gravitational force is a force of attraction that pulls two objects with masses together.

To best understand the concept of gravitational force, newton's law of universal gravitation provides a good insight. The law states that "every object in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".

From the law, we see that gravitational force is dependent on the masses of the object and their distances.  

6 0
3 years ago
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Weight is measured with a ___________. <br> Question 4 options: <br> A. Balance <br> B. Scale
kap26 [50]

Answer: B

Explanation: Scale

4 0
3 years ago
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Which of these help create radio waves?
Margaret [11]
The correct option is A.
All waves are divided into two basic classes, which are transverse and longitudinal waves. A transverse wave is a type of wave in which the medium of propagation vibrates at angle 90 degree in relation to the direction of propagation. Radio wave is an example of a transverse wave. 
5 0
3 years ago
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A 4g bullet, travelling at 589m/s embeds itself in a 2.3kg block of wood that is initially at rest, and together they travel at
VARVARA [1.3K]

Answer:

The  percentage of the kinetic energy that is left in the system after collision to that before is 0.174 %

Explanation:

Given;

mass of bullet, m₁ = 4g = 0.004kg

initial velocity of bullet, u₁ = 589 m/s

mass of block of wood, m₂ = 2.3 kg

initial velocity of the block of wood, u₂ = 0

let the final velocity of the system after collision = v

Apply the principle of conservation of linear momentum

m₁u₁ + m₂u₂ = v(m₁+m₂)

0.004(589) + 2.3(0) = v(0.004 + 2.3)

2.356 = 2.304v

v = 2.356 / 2.304

v = 1.0226 m/s

Initial kinetic energy of the system

K.E₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

K.E₁ = ¹/₂(0.004)(589)² = 693.842 J

Final kinetic energy of the system

K.E₂ = ¹/₂v²(m₁ + m₂)

K.E₂ = ¹/₂ x 1.0226² x (0.004 + 2.3)

K.E₂ = 1.209 J

The kinetic energy left in the system = final kinetic energy of the system

The percentage of the kinetic energy that is left in the system after collision to that before = (K.E₂ / K.E₁) x 100%

                       = (1.209 / 693.842) x 100%

                        = 0.174 %

Therefore, the  percentage of the kinetic energy that is left in the system after collision to that before is 0.174 %

6 0
3 years ago
A 2.00 meter long horizontal plank whose mass is 3.00 kg is placed so that the very end (the right end) rests on a retaining wal
avanturin [10]

Answer:

R_g=\frac{61}{7} =8.7143\ N

R_w=45.1857\ N

Explanation:

Given that:

  • mass of plank, m=3\ kg
  • length of plank, l=2\ m

From the image we can visualize the given situation.

Consider the given plank to be mass-less and having a uniformly distributed mass of 1.5 kg per meter.

<u>Now in the balanced condition:</u>

  • \sum F=0

R_g+R_w=(3+2.5)\times 9.8

R_g+R_w=53.9\ N .......................(1)

  • \sum M_w=0

1.75\times R_g=3\times 1+(2.5\times 9.8)\times 0.5

R_g=\frac{61}{7} =8.7143\ N ...........................(2)

is the force acted by the tailgate on the plank.

<u>Substitute the value from (2) into (1):</u>

R_w=45.1857\ N is the force acted by the wall upon the plank.

6 0
3 years ago
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