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3 years ago

14

A uniform charge density of 600 nC/m3 is distributed throughout a spherical volume (radius = 14 cm). Consider a cubical (3.2 cm

along the edge) surface completely inside the sphere. Determine the electric flux through this surface.

1 answer:

jolli1 [7]3 years ago

5 0

Answer: The electric flux through this surface is 2.22 Nm^2/C

Explanation: Please see the attachments below

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Answer:

Tech B is correct and Tech A is incorrect.

Explanation:

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Answer:

$\dfrac{dz}{dt}=0.65\ ft/s$

Explanation:

Given that

x= 150 ft

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From the diagram

$z^2=x^2+y^2$

When ,x= 150 ft and y= 14 ft

$z^2=150^2+14^2$

$z=\sqrt{150^2+15^2}$

z=150.74 ft

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By differentiating with respect to time t

$2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}$

$z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}$

Here x is constant that is why

$\dfrac{dx}{dt}=0$

$z\dfrac{dz}{dt}= y\dfrac{dy}{dt}$

Now by putting the values in the above equation we get

$150.74\times \dfrac{dz}{dt}=14\times 7$

$\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s$

$\dfrac{dz}{dt}=0.65\ ft/s$

Therefore the distance between balloon and observer increasing with 0.65 ft/s.

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3 years ago

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Answer:

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