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Sever21 [200]
2 years ago
13

Use the same line to answer the questions

Physics
1 answer:
vichka [17]2 years ago
7 0

(a) The distance From A to B to M to N is 22 m, the displacement is 22 m, the speed is 4.4 m/s and the average velocity is 4.4 m/s.

(b) The distance From C to A to G to D is 24 m, the displacement is 2 m, the speed is 4.8 m/s and the average velocity is 0.4 m/s.

(c) The distance From J to I to E to H is 16 m, the displacement is -2 m, the speed is 3.2 m/s and the average velocity is -0.4 m/s.

(d) The distance From F to B to K to F is 32 m, the displacement is 0 m, the speed is 6.4 m/s and the average velocity is 0 m/s.

<h3>Distance traveled by the object</h3>

The distance traveled by the object is calculated as follows;

Distance From A to B to M to N

From A to B to M to N = 3 + 18 + 1 = 22

Distance From C to A to G to D

= 5 + 13 + 6

= 24

Distance From J to I to E to H

= 1 + 8 + 7

= 16

Distance from F to B to K to F

= 8 + 16 + 8

= 32

<h3>Displacement of the object</h3>

The displacement of the object is calculated as follows;

displacement = final position - initial position

Displacement From A to B to M to N

= 11 - (-11)

= 22

Displacement from C to A to G to D

= D - C

= - 4 - (-6)

= 2

Displacement from J to I to E to H

= H - J

= 5 - 7

= - 2

Displacement From F to B to K to F

= F - F

= 0

<h3>Speed of the object </h3>

The speed of the object is calculated as follows;

speed = total distance/total time

Speed of the object from A to B to M to N

= 22/5 = 4.4 m/s

Speed of the object from C to A to G to D

= 24/5

= 4.8 m/s

Speed of the object from J to I to E to H

= 16/5

= 3.2 m/s

Speed of the object from F to B to K to F

= 32/5

= 6.4 m/s

<h3>Average velocity of the object </h3>

The average velocity of the object is calculated as follows;

Average velocity from A to B to M to N

= 22/5

= 4.4 m/s

Average velocity of the object from C to A to G to D

= 2/5

= 0.4 m/s

Average velocity of the object from J to I to E to H

= -2/5

= -0.4 m/s

Average velocity of the object from F to B to K to F

= 0

Learn more about average velocity here: brainly.com/question/24445340

#SPJ1

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Suppose that two point charges, each with a charge of +1.00 C, are separated by a distance of 1.0 m. If the distance between the
Aleksandr-060686 [28]

Given:

The magnitude of each charge is q1 = q2 = 1 C

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To find the force when distance is doubled.

Explanation:

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\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}

The force can be calculated by the formula

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Read 2 more answers
A person throws a ball straight up. He releases the ball at a height of 1.75 m above the ground and with a velocity of 12.0 m/s.
Lyrx [107]

Answer:

a) 1.22 s

b) 9.089 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-12}{-9.81}\\\Rightarrow t=1.22\ s

Time taken by the ball to reach the highest point is 1.22 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=12\times 1.22+\frac{1}{2}\times -9.81\times 1.22^2\\\Rightarrow s=7.339\ m

The maximum height the ball will reach above the ground is 1.75+7.339 = 9.089 m

8 0
3 years ago
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