All categories

2 years ago

Use the same line to answer the questions

Physics

1 answer:

vichka [17]2 years ago

7 0

(a) The distance From A to B to M to N is 22 m, the displacement is 22 m, the speed is 4.4 m/s and the average velocity is 4.4 m/s.

(b) The distance From C to A to G to D is 24 m, the displacement is 2 m, the speed is 4.8 m/s and the average velocity is 0.4 m/s.

(c) The distance From J to I to E to H is 16 m, the displacement is -2 m, the speed is 3.2 m/s and the average velocity is -0.4 m/s.

(d) The distance From F to B to K to F is 32 m, the displacement is 0 m, the speed is 6.4 m/s and the average velocity is 0 m/s.

<h3>Distance traveled by the object</h3>

The distance traveled by the object is calculated as follows;

Distance From A to B to M to N

From A to B to M to N = 3 + 18 + 1 = 22

Distance From C to A to G to D

= 5 + 13 + 6

= 24

Distance From J to I to E to H

= 1 + 8 + 7

= 16

Distance from F to B to K to F

= 8 + 16 + 8

= 32

<h3>Displacement of the object</h3>

The displacement of the object is calculated as follows;

displacement = final position - initial position

Displacement From A to B to M to N

= 11 - (-11)

= 22

Displacement from C to A to G to D

= D - C

= - 4 - (-6)

= 2

Displacement from J to I to E to H

= H - J

= 5 - 7

= - 2

Displacement From F to B to K to F

= F - F

= 0

<h3>Speed of the object </h3>

The speed of the object is calculated as follows;

speed = total distance/total time

Speed of the object from A to B to M to N

= 22/5 = 4.4 m/s

Speed of the object from C to A to G to D

= 24/5

= 4.8 m/s

Speed of the object from J to I to E to H

= 16/5

= 3.2 m/s

Speed of the object from F to B to K to F

= 32/5

= 6.4 m/s

<h3>Average velocity of the object </h3>

The average velocity of the object is calculated as follows;

Average velocity from A to B to M to N

= 22/5

= 4.4 m/s

Average velocity of the object from C to A to G to D

= 2/5

= 0.4 m/s

Average velocity of the object from J to I to E to H

= -2/5

= -0.4 m/s

Average velocity of the object from F to B to K to F

= 0

Learn more about average velocity here: brainly.com/question/24445340

#SPJ1

You might be interested in

Why is an iron bolt attracted to a magnet?

icang [17]

Answer:

A. When it is in a magnetic field, it becomes a temporary magnet.

Explanation:

An iron bolt is attracted to a magnet because when in a magnetic field, the iron becomes a temporary magnet.

This is because the iron aligns their electrons in the magnetic fields.

This causes that attraction between the magnet and the iron.
Metals like iron are said to be ferromagnetic
Unpaired electrons in iron spin in such a way that they align with the magnetic fields of the magnet.

8 0

3 years ago

Read 2 more answers

A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve

Troyanec [42]

The velocity of tennis racket after collision is 14.96m/s

<u>Explanation:</u>

Given-

Mass, m = 0.311kg

u1 = 30.3m/s

m2 = 0.057kg

u2 = 19.2m/s

Since m2 is moving in opposite direction, u2 = -19.2m/s

Velocity of m1 after collision = ?

Let the velocity of m1 after collision be v

After collision the momentum is conserved.

Therefore,

m1u1 - m2u2 = m1v1 + m2v2

$v1 = (\frac{m1-m2}{m1+m2})u1 + (\frac{2m2}{m1+m2})u2$

$v1 = (\frac{0.311-0.057}{0.311+0.057})30.3 + (\frac{2 X 0.057}{0.311 + 0.057}) X-19.2\\\\v1 = (\frac{0.254}{0.368} )30.3 + (\frac{0.114}{0.368}) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96$

Therefore, the velocity of tennis racket after collision is 14.96m/s

7 0

3 years ago

QUESTION 10

Elena L [17]

The maximum value of θ of such the ropes (with a maximum tension of 5,479 N) will be able to support the beam without snapping is:

$\theta =37.01^{\circ}$

We can apply the first Newton's law in x and y-direction.

If we do a free body diagram of the system we will have:

x-direction

All the forces acting in this direction are:

$T_{1}sin(\theta)-T_{2}sin(\theta)=0$ (1)

Where:

T(1) is the tension due to the rope 1
T(2) is the tension due to the rope 2

Here we just conclude that T(1) = T(2)

y-direction

The forces in this direction are:

$T_{1}cos(\theta)+T_{2}cos(\theta)-W=0$ (2)

Here W is the weight of the steel beam.

We equal it to zero because we need to find the maximum angle at which the ropes will be able to support the beam without snapping.

Knowing that T(1) = T(2) and W = mg, we have:

$T_{1}cos(\theta)+T_{1}cos(\theta)-m_{steel}g=0$

$2T_{1}cos(\theta)-m_{steel}g=0$

$2T_{1}cos(\theta)=m_{steel}g$

T(1) must be equal to 5479 N, so we have:

$cos(\theta)=\frac{m_{steel}g}{2T_{1}}$

$cos(\theta)=\frac{892*9.81}{2*5479}$

$cos(\theta)=0.80$

Therefore, the maximum angle allowed is θ = 37.01°.

You can learn more about tension here:

brainly.com/question/12797227

I hope it helps you!

8 0

3 years ago

Which of the following is an example of how culture can help humans

serg [7]

A prime example of how culture has contributed to human survival is the development of agriculture, which helps feed enormous numbers of people. Option A is correct.

<h3 /><h3>What is culture?</h3>

A population's collective ways of life are known as culture. The manner of life for an entire society has been said about culture. It encompasses manners, rituals, and artistic standards.

The invention of farming helps feed large populations of humans and is an example of how culture can help humans survive.

Hence option A is correct.

To learn more about the culture refer to:

brainly.com/question/12678729

#SPJ1

7 0

2 years ago

if a car that is 100 feet in front of you on route 70 west slams on the brakes while you are traveling 65 miles per hour (95 fee

fenix001 [56]

Answer:

t = 1.05 s

Explanation:

Given,

The distance between your vehicle and car, 100 ft

The constant speed of your vehicle, u = 95 ft/s

Since, the velocity is constant, a =0

If the car stopped suddenly, time left for you to hit the brake, t = ?

Using the second equation of motion,

S = ut + ½ at²

Substituting the given values in the equation

100 = 95 x t

t = 100/95

= 1.05 s

Hence, the time left for you to hit the brakes and stop before rear ending them, t = 1.05 s

5 0

3 years ago