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3 years ago

11

What is the acceleration of this object? The object's mass is 2 kg. Small box with dot in the middle. Arrows originate at dot. A

rrow up and Arrow down are same length. Arrow up labeled F sub norm equals 20 N and Arrow down labeled F sub grav equals 20 N. Arrow to the right is longer than arrow to the left. Arrow to the right is labeled F sub app equals 22 N and arrow to the left is labeled F sub frict equals 14 N. 11 m/s2 0 m/s2 4 m/s2 7 m/s2

2 answers:

Murrr4er [49]3 years ago

8 0

Answer:

4 m/s2

Explanation:

I took the test

weeeeeb [17]3 years ago

8 0

Answer:

4m/s2

Explanation:

i took the test

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How does the kinetic energy of a charge change as the charge moves under the effect of an electric field from higher potential t

77julia77 [94]

Answer:The kinetic energy will decrease.

Explanation:As potential energy increases kinetic energy will increase, as kinetic or potential energy decreases, the kinetic or potential energy will decrease

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3 years ago

What is a phenomenon in your own words?

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Answer: 1 : an observable fact or event. 2a : an object or aspect known through the senses rather than by thought or intuition. b : a fact or event of scientific interest susceptible of scientific description and explanation. More from Merriam-Webster on phenomenon.

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3 years ago

Read 2 more answers

a car drives 40 miles east, turns around, then drives 30 miles west. (a) Find the distance traveled by the car. (b) find the car

Dovator [93]

Part A)

Distance is given as sum of total path length

So here as we are given that car drives 40 miles East and 30 miles West

So here the total path length is

$Distance = 40 miles + 30 miles$

$distance = 70 miles$

Part B)

Displacement is given as straight line distance between initial and final position

So here we can see that

$d_1 = 40 miles$ East

$d_2 = 30 miles$ West

Now the total displacement will be

$d = d_1 - d_2 = 40 - 30 = 10 miles$

<u><em>so the displacement will be 10 miles East</em></u>

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3 years ago

A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.

Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

k x = m g

$k = \dfrac{mg}{x}$

$k = \dfrac{6.4 \times 9.8}{0.28}$

k = 224 N/m

b) $f = \dfrac{\omega}{2\pi}$

$\omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}$

$f =0.94\ Hz$

c) $v_b = -v cos \omega t$

$v_b = -5.1 \times cos (5.92 \times 0.42)$

$v_b = 4.04\ m/s$

d) $a_{max} = v \omega$

$a_{max} = 4.04 \times 5.92$

$a_{max} =23.94\ m/s^2$

e) $Y =- A sin (\omega t)$

$A = \dfrac{v}{\omega}$

$A = \dfrac{4.04}{5.92}$

A = 0.682 m

$Y =- 0.682 \times sin (5.92 \times 0.42)$

$Y =- 0.42$

Force = $m \omega^2 |Y|$

= $6.4 \times 5.92^2\times 0.42$

F = 94.20 N

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3 years ago

A world-class tennis player can serve a tennis ball at 150 mi/h (about 67 m/s). The length of a tennis

Rudik [331]

Answer:

The expression for the time taken by an object to move with a speed at some distance is,

t=<u> </u><u>d</u><u>/</u><u>v</u>

Here, t is the time taken by the opponent to react, d is the length of the court, andis the speed of the ball.

Explanation:

hope u like it :)

5 0

3 years ago