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Scilla [17]
4 years ago
11

A skateboarder rolls off a horizontal ledge that is 1.32m high and lands 1.88m from the base of the ledge. What was the initial

velocity? (Unit=m/s)
Physics
1 answer:
NemiM [27]4 years ago
4 0

Answer:

Velocity = 3.622 m/s

Explanation:

Given:

Starting height = 1.32 m

Distance = 1.88 m

Find:

Velocity

Computation:

Using 2nd equation of motion.

s = ut + [1/2]gt²  , where g = 9.8 m/s² and u = 0

1.32 = [1/2][9.8]t²

Time (t) = 0.519 sec

We know that

Velocity = Distance / Time

Velocity = 1.88 / 0.519

Velocity = 3.622 m/s

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The work output of a machine can never be less than
Dominik [7]
The work output of a machine can be anything, depending on the friction
and other losses internal to the machine. But it can never be MORE than
the work <u>input</u>.

I suppose you might say that the work output can never be less than zero,
because there's no such thing as negative energy.
5 0
3 years ago
During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where i
alukav5142 [94]

Answer:

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

d=vt+\frac{1}{2}at^2

Now by substituting values in, we get

d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2

d = 19.796m

7 0
3 years ago
3.
Alexxx [7]

Answer:

120°

Explanation:

Draw a free body diagram.  There are three forces acting on the traffic light.  Two tension forces acting along the cables, and weight.

The tension forces have an angle θ between them.  That means each tension force forms an angle of θ/2 with respect to the vertical.  So the y component of each tension force is:

Ty = T cos (θ/2)

Sum of the forces in the y direction:

∑F = ma

Ty + Ty − W = 0

2 Ty = W

Substituting:

2 T cos (θ/2) = W

If W = T, then:

2 W cos (θ/2) = W

2 cos (θ/2) = 1

cos (θ/2) = 1/2

θ/2 = 60°

θ = 120°

6 0
4 years ago
If 5kg Stone and 1kg stone throw the from the building which will land more fa ster and why?​
sweet [91]

Answer:

Both stones will land at the same time because both stones will fall with the same acceleration through the same height.

Explanation:

We are given that

Mass of stone ,m1=5 Kg

Mass of stone, m2=1 kg

We have to find which stone more faster will land and why.

h=u+\frac{1}{2}gt^2

Initial velocity of both stones=0

h=\frac{1}{2}gt^2

t^2=\frac{h}{g}

t=\sqrt{\frac{h}{g}}

t_1=t_2=\sqrt{\frac{h}{g}}

Because both stones are thrown from the same height.

Both stones will land at the same time because both stones will fall with the same acceleration through the same height  and the acceleration  does not depend of its mass.

5 0
3 years ago
What is the period of a spring that oscillates with a frequency of 2.09 Hz​
Sergio [31]

Frequency, υ = 2.09 Hz

We know that time period, T = 1/υ

∴ T = 1 ÷ 2.09

⇒ T = 0.4784 seconds

5 0
4 years ago
Read 2 more answers
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