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baherus [9]
3 years ago
7

Which phrase best descubes the translation from the graph y = (x - 5)2 + 7 to the graph of y = (x + 1)2 - 2?

Mathematics
1 answer:
Ber [7]3 years ago
6 0

Answer:

"6 units left and 9 units down"

Step-by-step explanation:

Suppose a function is given in this form:

y=(x-a)^2+b

This is the parent function y = x^2

  • translated a units right (left if there was a + before a)
  • translated b units up (down if there was a - before b)

Now, to go from  y=(x-5)^2+7  to  y= (x+1)^2-2 , we can see that:

  • first function is 5 units right and 2nd one is 1 unit left, so there is a horizontal translation of 6 units left
  • first function is 7 units above and 2nd one is 2 units down, so there is a vertical translation of 9 units down

Thus, "6 units left and 9 units down" is the transformation(translation).

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-5c+d=2c

Add 5c to each side

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d = 7c

Divide each side by 7

d/7 = 7c/7

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Please show your work this question what made you come to the conclusion. Thank you
AveGali [126]

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B the range, the x- and y-intercept

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the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.

the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

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3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

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