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3 years ago

A risk is the likelihood of a threat source taking advantage of a vulnerability to an

Business

1 answer:

Citrus2011 [14]3 years ago

5 0

Answer:

B. Residual risks

Explanation:

Residual risks -

It refers to the amount of risk from any action , which is left after the removal of the inherent risk or the natural risk , is referred to as residual risks.

The value for the residual risk can be calculated as -

Residual risk = inherent risk - impact of risk controls.

Hence , from the scenario of the question,

The correct term is residual risk .

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A company issued 70 shares of $30 par value preferred stock for $4,000 cash. The journal entry to record the issuance is:______.

PtichkaEL [24]

Answer:

E. Debit Cash $4,000; credit Paid-in Capital in Excess of Par Value, Preferred Stock $1,900, credit Preferred Stock $2,100.

Explanation:

Journal Entry for Issuance of 70 shares of $30 par value preferred stock for $4,000 is -

Cash Debited - $4,000

Paid in Capital in excess of Par value Credited - $1,900

Preferred Stock (70 shares × $30 each) Credited - $2,100

The correct option is - E. Debit Cash $4,000; credit Paid-in Capital in Excess of Par Value, Preferred Stock $1,900, credit Preferred Stock $2,100.

7 0

3 years ago

Suppose that the market demand curve for bean sprouts is given by P = 1,660 - 4Q, where P is the price and Q is total industry o

a_sh-v [17]

Answer:

In equilibrium, total output by the two firms will be option e= 300.

Q = $q_{1}$ + $q_{2}$

Q = 100 + 200

Q = 300

Explanation:

Data Given:

Market Demand Curve = P = 1660-4Q

where, P = price and Q = total industry output

Each firm's marginal cost = $60 per unit of output

So, we know that Q = $q_{1}$ + $q_{2}$

where $q_{}$ being the individual firm output.

Solution:

P = 1660-4Q

P = 1660- 4( $q_{1}$ + $q_{2}$ )

P = 1660 - 4 $q_{1}$ - 4 $q_{2}$

Including the marginal cost of firm 1 and multiplying the whole equation by $q_{1}$

Let's suppose new equation is X

X = 1660 $q_{1}$ - 4 $q_{1} ^{2}$ - 4 $q_{1}$ $q_{2}$ - 60 $q_{1}$

Taking the derivative w.r.t to $q_{1}$ , we will get:

$X^{'}$ = 1660 - 8 $q_{1}$ - 4 $q_{2}$ - 60 = 0

Making rearrangements into the equation:

8 $q_{1}$ + $q_{2}$ = 1660 - 60

8 $q_{1}$ + $q_{2}$ = 1600

Dividing the whole equation by 4

2 $q_{1}$ + $q_{2}$ = 400

Solving for $q_{1}$

2 $q_{1}$ = 400 - $q_{2}$

$q_{1}$ = 200 - 0.5 $q_{2}$

Including the marginal cost of firm 1 and multiplying the whole equation by $q_{2}$

P = 1660 - 4 $q_{1}$ - 4 $q_{2}$

Let's suppose new equation is Y

Y = 1660 $q_{2}$ - 4 $q_{1}$ $q_{2}$ -4 $q_{2} ^{2}$ - 60 $q_{2}$

Pugging in the value of $q_{1}$

Y = 1660 $q_{2}$ - 4 $q_{2}$ (200 - 0.5 $q_{2}$ ) -4 $q_{2} ^{2}$ - 60 $q_{2}$

Y = 1660 $q_{2}$ - 800 $q_{2}$ +2 $q_{2} ^{2}$ -4 $q_{2} ^{2}$ - 60 $q_{2}$

Y = 1600 $q_{2}$ - 800 $q_{2}$ -2 $q_{2} ^{2}$

Taking the derivative w.r.t $q_{2}$

$Y^{'}$ = 1600 - 800 - 4 $q_{2}$ = 0

Solving for $q_{2}$

4 $q_{2}$ = 800

$q_{2}$ = 200

$q_{1}$ = 200 - 0.5 $q_{2}$

Plugging in the value of $q_{2}$ to get the value of $q_{1}$

$q_{1}$ = 200 - 0.5 (200)

$q_{1}$ = 200 - 100

$q_{1}$ = 100

Q = $q_{1}$ + $q_{2}$

Q = 100 + 200

Q = 300

Hence, in equilibrium, total output by the two firms will be option

e= 300.

5 0

3 years ago

Acme Enterprises began the new year owing its suppliers $3,000 for merchandise purchased last year. Acme then sold half of this

Sedaia [141]

Answer:

Acme's current balance of accounts payable is $6000

Explanation:

The closing balance of accounts payable can be calculated using the opening balance and adjusting the changes during the period to the opening balance.

The closing balance can thus be calculated as:

Closing balance = Opening balance + Credit purchases - Payment to Accounts payable

Closing balance = 3000 + 4000 - 1000

Closing balance = $6000

8 0

3 years ago

Isaiah is lucky to have such talented friends. Here’s where you come in:

anygoal [31]

Answer:

I can't figure it out sorry

5 0

3 years ago

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In a relationalâ database, the three basic operations used to develop useful sets of dataâ are:

Vitek1552 [10]

E is the correct answer

8 0

3 years ago