Answer:
1/8 · 8 = 1
Step-by-step explanation:
or 1
hope this helps
y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Just divide 300 by 450, to get 0.66667, which can be expressed as a fraction by 2/3
Answer:
5x +10
Step-by-step explanation:
3(x+2)+2(x+2)
Distribute
3x+6 +2x+4
Combine like terms
5x +10
It would be an obtuse angle :)