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3 years ago

PLEASE ANSWERS BOO'S!!!!

Mathematics

2 answers:

kiruha [24]3 years ago

7 0

The answer is a and remember to use the pythagorean theorem to answer these questions. The numbers are usually listed leg, leg, hypotenuse.

Brilliant_brown [7]3 years ago

3 0

Answer:

5, 12, 13

Step-by-step explanation:

Look at the first set of side lengths. If these lengths satisfy the Pythagorean Theorem, then we can correctly conclude that they represent a right triangle. Do the lengths 5, 12 and 13 satisfy the Pyth. Thm.?

In other words, does the sum of 5² and 12² equal 13²?

Does 25 + 144 =equal 169? YES. So yes, 5, 12 and 13 do represent a right triangle.

Second case: 4, 4 and 8. Does 16 + 16 equal 64? NO. Not a right triangle.

Third case: 2, 3, 4. Does 4 + 9 = 16? NO. Not a right triangle.

Summary: only 5, 12, 13 represent the side lengths of a right triangle.

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Hey, on the answer, can you provide steps? I do wanna know the actual content, but im dumb :P

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2 years ago

Find the product simplify the answer 3*1/7

Pani-rosa [81]

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Step-by-step explanation:

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2 years ago

Translate the following verbal expression into a algebraic expression Ten more than the absolute value of a number

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Answer:

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Step-by-step explanation:

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6 0

3 years ago

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

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3 years ago

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Answer:

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2 years ago