Question

A cylinder contains 3.0 L of oxygen at 310 K and 2.5 atm. The gas is heated, causing a piston in the cylinder to move outward. The heating causes the temperature to rise to 610 K and the volume of the cylinder to increase to 9.5 L. What is the gas pressure? P= _____atm

Answer 1

Answer:

The gas pressure is: 1.55 atm.

Explanation:

We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion $PV=nRT$ to $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2} }$ solving to P2 we get:$\frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}=P_{2}$ replace the values $P_{2}=\frac{2.5*3*610}{9.5*310} =1.55(atm)$.