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Natasha2012 [34]

3 years ago

9

A cylinder contains 3.0 L of oxygen at 310 K and 2.5 atm. The gas is heated, causing a piston in the cylinder to move outward. T

he heating causes the temperature to rise to 610 K and the volume of the cylinder to increase to 9.5 L. What is the gas pressure? P= _____atm

1 answer:

Alex_Xolod [135]3 years ago

5 0

Answer:

The gas pressure is: 1.55 atm.

Explanation:

We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion $PV=nRT$ to $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2} }$ solving to P2 we get: $\frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}=P_{2}$ replace the values $P_{2}=\frac{2.5*3*610}{9.5*310} =1.55(atm)$ .

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a crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one

prohojiy [21]

The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be $37^o$ C is 367.42 Hz.

A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.

The fundamental frequency in the tube is given by

$f=\frac{v_T}{4L}$

where, $v_T=v\sqrt{\frac{T}{273} }$

Since, T=37+273 K = 310 K

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$\therefore v_T=331\sqrt{\frac{310}{273} } = 352.72 \ m/s$

Using this, we get:

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2 years ago

Newton’s empirical law of cooling/warming of an object is given by ( ), T Tm k dt dT = − where k is a constant of proportionalit

pychu [463]

Answer:

The time for the cake to cool off to room temperature is

approximately 30 minutes.

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Our Tm = 70, the initial-value problem is

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Solving the equation, we get

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Finding he value for $C_{2}$ using the initial value of T (0)= 300, therefore we get:

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Finding the value for <em>k </em>using T (3) = 200, therefore we get

T (3) = 200

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= -0.19018

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3 years ago

A 10-foot ladder is leaning straight up against a wall when a person begins pulling the base of the ladder away from the wall at

docker41 [41]

Answer:

$y = 4.36$

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<em>Hence, the true distance at that point is approximately 4.36ft</em>

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Answer:

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Explanation:

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