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Vanyuwa [196]
4 years ago
11

Which kind of illustration would you use to show a history of genetic characteristics in a family?

Physics
1 answer:
borishaifa [10]4 years ago
5 0
Pedigree. it’s like a family tree

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A plane has a takeoff speed of 89.3m/s and requires 1465m to reach that speed determine the acceleration of the plane and the ti
Tems11 [23]

Answer:

a = 2.72 ms⁻²

32.83 s

Explanation:

By using the kinematic equations you get,

v² = u² +2as and v = u + at   where all terms in usual meaning

Using 1st equation,

89.3² = 0² + 2a×1465 ⇒ a = 2.72 ms⁻²

By 2nd equation,

89.3 = 0 + 2.72×t ⇒ t = 32.83 s

4 0
3 years ago
____________are necessary to explain research findings.
Elodia [21]

Answer:

C. Theories

Explanation:

Theories basically explain why of research findings. By definition, theories help us understand, explain, and predict the occurrence of a phenomena. In research, theories support research findings by explaining how the variables involved influence each other not merely based on observation during this one experiment. It also helps validate the findings by relating it to theories of previous work.

5 0
3 years ago
A car with an initial speed of 4.30 m/s accelerates at a rate of 3 ms^2. What is the car's speed after 5 s?
Lorico [155]

Answer:

v = u + at

u = 4.30 m/s

a = 3 m/s^2

t = 5 s

v = 4.30 + (3)(5)

v = 4.30 + 15

v = 19.30 m/s

Explanation:

Hope this helps!

5 0
3 years ago
scrieti in caiete substantivele ,adjectivele sau verbele apartinand familiei lexicale a urmatoarelor cuvinte din text : inima,ar
ser-zykov [4K]
Yes the answer is yes, all the way yes
5 0
3 years ago
A steel playground slide is 5.25 m long and is raised 2.75 m on one end. A 45.0 kg child slides down from the top starting at re
Temka [501]

Answer:

F=32.24N

Explanation:

From the question we are told that:

Height h= 2.75 m

Lengthl = 5.25 m

Mass m=45kg

Final speed v_f=6.81

Generally the equation for Potential Energy P.E is mathematically given by

P.E=mgh

Therefore

Initial potential energy

P.E_1=45*9.8*2.75 \\\\P.E_1= 1212.75 J

Generally the equation for Kinetic Energy K.E is mathematically given by

K.E=0.5mv^2

Therefore

Final kinetic energy

K.E_2= 1/2*45*6.81*6.81 \\\\K.E_2= 1043.46J

Generally the equation for Work_done is mathematically given by

W=P.E_1-K.E_2\\\\W=169.3

Therefore

F=\frac{W}{d}\\\\F=\frac{169.3}{5.25}

F=32.24N

8 0
3 years ago
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