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3 years ago

I just need a full answer here not only so I can answer the question, but also so that I can learn.

1 answer:

7 0

Answer: Number of valence electrons determine how fast or easy for an atom to gain stability. Either by gaining electrons or by losing electrons.

Group one and seven elements react fast because they only have one electron to gain or lose.

Explanation:

Number of valence electrons tell us the number of electrons an atom will gain or lose in order to attain stability in electron configuration.

All the elements in a particular group will have the same number of valence electrons as follows:

Group one - 1 valence electron

Group two - 2 valence electrons

Group three - 3 valence electrons

Group four - 4 valence electrons

Group five - 3 valence electrons

Group six - 2 valence electrons

Group seven - 1 valence electron

Group eight - 0 valence electron

Some elements are more reactive than the others because of the electron affinity, oxidation state and electronegativity of the atoms

For instance, elements in group 7 are more reactive than others because of their oxidation state and they have very high electronegativity.

Also, group one elements are more reactive because they only have one electron to loose.

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Waves begin to "feel bottom" when the depth of water is

LekaFEV [45]

I think the correct answer would be one half the wavelength. Waves would "feel bottom" when the water is at the depth of 0.5 of the wavelength. "Feel bottom" is a term used to describe that the depth of water affects the wave properties. Hope this answers the question.

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3 years ago

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Which lists types of materials from most conductive to least conductive?

Lilit [14]

Superconductor, conductor, semiconductor, insulator

7 0

3 years ago

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What is one way to take advantage of creating even more kinetic energy on this particular technologically advanced field

ch4aika [34]

Incomplete question. However, I provided a brief about Kinetic energy generation.

<u>Explanation:</u>

Interestingly, Kinetic energy in simple terms refers to the energy possessed by a body in motion.

It is often calculated using the formula E = $\frac{1}{2}MV^{2}$

A good example of creating even more kinetic energy is a hand crank toy car that moves after you wind it a little, when the car moves it is generating another measure of K.E.

7 0

3 years ago

A 4.4 nC charge exerts a repulsive force of 36 mN on a second charge which is located

zhenek [66]

The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.

They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.

The given data in the problem is;

q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C

F is the repulsive force = 36 mN =36 ×10⁶ N

d is the distance = 0.70 m

The Coulomb force is found as;

$\rm F = \frac{Kq_1q_2}{r^2}\\\\\ \rm 36\times 10^6 = \frac{9 \times 10^9 }{(0.7)^2} \times 4.4 \times 10^{-9} \times q_2\\\\\ q_2 = 8.6241 \times 10^{-19 } \ C$

Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.

To learn more about Coulomb's law, refer to the link;

brainly.com/question/1616890

#SPJ2

6 0

2 years ago

Two speedboats are traveling at the same speed relative to the water in opposite directions in a moving river. An observer on th

DENIUS [597]

Answer:

a) vboat = 5.95 m/s b) vriver= 1.05 m/s

Explanation:

a) As observed from the shore, the speed of the boats can be expressed as the vector sum, of the boat speed relative to the water and the river speed relative to the shore, as follows:

vb₁s = vb₁w + vrs

In one case, the boat is moving in the same direction as the water:

vb₁s = vb₁w + vrs = 7.0 m/s (1)

For the other boat, it is clear that is moving in an opposite direction:

vb₂s = vb₂w - vrs = 4.9 m/s (2)

As we know that vb₁w = vb₂w, adding both sides, we can remove the river speed from the equation, as follows:

vb₁w = vb₂w = $\frac{7.0 m/s + 4.9 m/s}{2} =5.95 m/s$

b) Replacing this value in (1) and solving for vriver, we have:

vriver = 7.0 m/s - 5.95 m/s = 1.05 m/s

(we could have arrived to the same result subtracting both sides in (1), and (2))

3 0

3 years ago