Answer:
A
Explanation:
Actual output divided by the effective capacity. It is the ratio of output to effectiveness
1st <span>the total </span>energy<span> of an </span>isolated system<span> is constant; energy can be transformed from one form to another, but can be neither created nor destroyed. ▲U=Q-W
</span><span>
2nd the total </span>entropy<span> can never decrease over time for an </span>isolated system, that is, a system in which neither energy nor matter can enter nor leave.
DS (Greater than or equal to) 0
The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
The mass of the baseball, m = 0.15 kg
The speed at which it moves, v = 30 m/s
Time at which the baseball was in contact with the bat, t = 0.75 ms
t = 0.75/1000 s
t = 0.00075 s
The impulsive force is given by the formula:

Substitute m = 0.15 kg, v = 30, and t = 0.00075s into the formula above:

The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
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Answer:
See the explanation below,
Explanation:
Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
A)

B)
![P=100*5\\P=500[kg*m/s]](https://tex.z-dn.net/?f=P%3D100%2A5%5C%5CP%3D500%5Bkg%2Am%2Fs%5D)
C)
![P=1200*15\\P=18000[kg*m/s]](https://tex.z-dn.net/?f=P%3D1200%2A15%5C%5CP%3D18000%5Bkg%2Am%2Fs%5D)
D)
![P=15*1000\\P=15000[kg*m/s]](https://tex.z-dn.net/?f=P%3D15%2A1000%5C%5CP%3D15000%5Bkg%2Am%2Fs%5D)
From higher to lower momentum
C,D,B,A
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Weight = electric force
<span>mg = qE </span>
<span>6.64x10^-27 x 9.81 = (2 x 1.60x10^-19) E
</span>qE =mg,
<span>E = mg/q = 6.64•10^-27•9.8/2•1.6•10^-19 =2.03•10^-7 V/m</span>