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2 years ago

Explain how knowing the divisibility rule for 10 can help you make a factor tree for multiples of 10

1 answer:

8 0

every number is divisible by 1 (Identity property)
A number is divisible by 2 if it is even (ends in 0,2,4,6,or 8)
A number is divisible by 3 if the sum of the digits in the number is divisible by 3.
A number is divisible by 4 if the last two digits are divisible by 4
A number is divisible by 5 if it ends in a 5 or a 0.
A number is divisible by 6 if it is divisible by 2 and 3 (use both those rules.)
A number is divisible by 9 if the sum of its digits is divisible by 9.
A number is divisible by 10 if it ends in a 0.

So by these rules
The sum of the digits are 8 + 0 = 8 so it is not divisible by 3 or 9.
1, 80
2, 20
4, 20
5, 16
10, 8
have a great day!

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Need help pls!!! Hurry

Olin [163]

Answer:

-1÷ 5 = -0.2

-0.2×4=-0.8 = -4/5

I hope that was helpful

7 0

2 years ago

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .

The equation for a sphere of radius $r$ and center $\left(x_0,\, y_0,\, z_0\right)$ would be:

$\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2$ .

In this case, the equation would be:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2$ .

Simplify to obtain:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56$ .

Expand the squares and simplify to obtain:

$x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ .

8 0

2 years ago

Find the Solution of the system of equations. -4x+3y=-21 -2x-3y=3

LUCKY_DIMON [66]

Answer:

(3, - 3)

Step-by-step explanation: that might be it

8 0

2 years ago

What is the answer for 4x < 25

VLD [36.1K]

Answer:

$x$

Step-by-step explanation:

$4x$

6 0

2 years ago

IF YOUR GOOD AT MATH PLZ HELP ME!!!!!!I WILL MAKE YOUR ANSWER BRAINLIEST

Solnce55 [7]

M(1, 2) , P(1, 3) , A(3, 3) , and T(3, 2)

1 unit right and 2 units up

this is your answer... (first choice)

M'(2, 4) , P'(2, 5) , A'(4, 5) , and T'(4, 4)

8 0

2 years ago