Step-by-step explanation:
3 - 2(b - 2) = 2 - 7b
To solve this first distribute -2 to (b - 2)
3 + (-2b + (-2) x -2) = 2 - 7b
when we simplify this it becomes:
3 + (-2b + 4) = 2 - 7b
We take (-2b + 4) out of the parenthesis:
3 - 2b + 4 = 2 - 7b
Now simplify again.
7 - 2b = 2 - 7b
Now send all the b's to one side and constants on the other.
7 - 2 = -7b +2b
5 = 5b
b = 1
Answer:
(f•g)(-5) = -238
Step-by-step explanation:
We have that:
f(x) = -3x + 2
g(x) = 4x + 6
Find (f•g)(-5).
First we find (f.g)(x)
So
f(x)*g(x) = (-3x + 2)*(4x + 6) = -12x² -10x + 12
When x = -5
-12(-5)² - 10(-5) + 12 = -238
(f•g)(-5) = -238
Just fill in the problem... 3*-2-1-3*-2
To best emphasize the number of defects. Manager should use graph 3 (refer the image shown):
If we talk about graph 1, it can also be used but usually we put the time line on the horizontal axis, for the convenience and the quantity to be measured on the y-axis. In the graph 1, the time is placed on the vertical axis (x-axis) so it would not be a good pick for the manager.
Same is the case with graph 2 again we have time on the vertical axis. So it is not a good idea to with graph 2.
Graph 3 could be the best to emphasize the number of defects because first of all time is placed on the horizontal axis and the quantity to be shown is on the vertical axis. Secondly, the range of the vertical axis is less so it is easy to observe the data set on the graph quite distinctively. Therefore, graph 3 is the best pick.
Graph 4 is placed correctly in terms of vertical and horizontal axes but the range of vertical axis is quite high due to which the dispersion or the display of the data is quite compressed and it gets hard to visualize.
<2 = 38
An iscolese triangle adds to 180 degrees. Thus, the two base angles, which is <2 & <3 should be half of the result from 180 - 104.
180 - 104 (angles in a triangle add to 180 degrees)
= 76
76 / 2 (iscolese triangle. base angles are equal)
therefore, 38