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4 years ago

What is hydrophobic tail??

Chemistry

1 answer:

puteri [66]4 years ago

8 0

Answer:

Hydrophobic molecules and surfaces repel water. Hydrophobic liquids, such as oil, will separate from water. Hydrophobic molecules are usually nonpolar, meaning the atoms that make the molecule do not produce a static electric field.

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The formula C2H4 can be described as

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It's describe as Ethylene

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Which of these properties is most helpful when identifying a substance in a given sample of matter

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Answer:

melting point

Explanation:

its one of the physical properties of a substance

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3 years ago

3. Find the mass of 4.77 x 1022 atoms of scandium (Sc).

iren2701 [21]

Answer:

Mass = 3.6 g

Explanation:

Given data:

Number of atoms of scandium = 4.77×10²² atoms

Mass of arsenic = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022× 10²³ is called Avogadro number.

one mole = 6.02×10²³ atoms

one mole × 4.77×10²² atoms / 6.02×10²³ atoms

0.08 mol

Mass of scandium

Mass = number of moles × molar mass

Mass = 0.08 mol × 45 g/mol

Mass = 3.6 g

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3 years ago

Calculate the radius of tantalum (Ta) atom, given that Ta has a BCC crystal structure, a density of 16.6 g/cm, and an atomic wei

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Answer:

The radius of tantalum (Ta) atom is $R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm$

Explanation:

From the Body-centered cubic (BBC) crystal structure we know that a unit cell length a and atomic radius R are related through

$a=\frac{4R}{\sqrt{3} }$

So the volume of the unit cell $V_{c}$ is

$V_{c}= a^3=(\frac{4R}{\sqrt{3} } )^3=\frac{64\sqrt{3}R^3}{9}$

We can compute the theoretical density ρ through the following relationship

$\rho=\frac{nA}{V_{c}N_{a}}$

where

n = number of atoms associated with each unit cell

A = atomic weight

$V_{c}$ = volume of the unit cell

$N_{a}$ = Avogadro’s number ( $6.023 \times 10^{23}$ atoms/mol)

From the information given:

A = 180.9 g/mol

ρ = 16.6 g/cm^3

Since the crystal structure is BCC, n, the number of atoms per unit cell, is 2.

We can use the theoretical density ρ to find the radio R as follows:

$\rho=\frac{nA}{V_{c}N_{a}}\\\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}$

Solving for R

$\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}\\\frac{64\sqrt{3}R^3}{9}=\frac{nA}{\rho N_{a}}\\R^3=\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}} \\R=\sqrt[3]{\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}$

Substitution for the various parameters into above equation yields

$R=\sqrt[3]{\frac{2\cdot 180.9}{16.6\cdot 6.023 \times 10^{23}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}\\R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm$

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4 years ago

How many moles of each element are in one mole of Be(OH)2?

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B. 1 mole of beryllium, 2 moles of oxygen, 2 moles of hydrogen

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3 years ago

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What is hydrophobic tail??​

What is hydrophobic tail??