Answer:
34.9 g/mol is the molar mass for this solute
Explanation:
Formula for boiling point elevation: ΔT = Kb . m . i
ΔT = Temperatures 's difference between pure solvent and solution → 0.899°C
Kb = Ebullioscopic constant → 0.511°C/m
m = molality (moles of solute/1kg of solvent)
i = 2 → The solute is a strong electrolyte that ionizes into 2 ions
For example: AB ⇒ A⁺ + B⁻
Let's replace → 0.899°C = 0.511 °C/m . m . 2
0.899°C / 0.511 m/°C . 2 = m → 0.879 molal
This moles corresponds to 1 kg of solvent. Let's determine the molar mass
Molar mass (g/mol) → 30.76 g / 0.879 mol = 34.9 g/mol
Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.
<h3>Which is the better chemical for an airbag?</h3>
The chemical equation for the production of nitrogen gas from sodium azide is given below:
1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.
The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:
- Na₂CO₃ + CH₃COOH → CH₃COONa + CO₂ + H₂O
1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.
The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.
In conclusion, sodium azide is a better choice in airbags.
Learn more about airbags at: brainly.com/question/14954949
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Answer:
Calcium atoms have smaller radii than potassium atoms since calcium atoms have a greater nuclear charge. Each calcium atom will be closer to the delocalized electrons. Thus, the bonds in calcium will be stronger than that in potassium.
Explanation:
The highest point of a wave<span> is </span>called<span> the </span>crest<span>. ... </span>Wave<span> height is the vertical </span>distance between<span> the </span>crest<span> and trough. Wavelength is the horizontal </span>distance between waves<span> in a series. Wavelength can be measured </span>between two wave crests<span>.</span>
Answer:
The molarity of this final solution is 0.167 M
Explanation:
Step 1: Data given
Volume of a 0.100 M HNO3 solution = 50.0 mL
Volume of a 0.200 M HNO3 = 100.0 mL
Step 2: Calculate moles
The final molarity must lie between 0.1M and 0.2M
Moles = molarity * volume
Moles HNO3 in 50mL of a 0.100M solution = 0.05 L *0.100 M = 0.005 mol
Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol
total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L
Step 3: Calculate molarity of final solution
Molarity = mol / volume
Molarity 0.025 moles /0.150 L
Molarity = 0.167M
The molarity of this final solution is 0.167 M
