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Ksenya-84 [330]
3 years ago
5

A spider can tell when its web has captured, say, a fly because the fly's thrashing causes the web threads to oscillate. A spide

r can even determine the size of the fly by the frequency of the oscillations. Assume that a fly oscillates on the capture thread on which it is caught like a block on a spring. What is the ratio of oscillation frequency for a fly with mass m to a fly with mass 2.00 m?
Physics
1 answer:
Aleonysh [2.5K]3 years ago
5 0

Answer:

Ratio of oscillation frequency is 1.41

Explanation:

Given

m2=2.00m

m1=m

The angular frequency is given as

w=\sqrt{\frac{K}{m} }\\ where \\T=2\pi \sqrt{\frac{m}{K} }

For two different masses m1 and m2

\frac{w_{1} }{w_{2}}=\sqrt{\frac{(\frac{K}{m1} )}{(\frac{K}{m2} )} }\\\frac{w_{1} }{w_{2}}=\sqrt{\frac{m2}{m1} }\\   \frac{w_{1} }{w_{2}}=\sqrt{2}\\ so\\ratio=1.41

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Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a
cupoosta [38]

Answer:

2.2 s

Explanation:

Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point =  mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)

So, T = 2π√(I/mgh)

T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

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