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Lilit [14]
3 years ago
12

A 10 kg box is pushed with a force of 20N. What is the box's acceleration?

Physics
1 answer:
Rasek [7]3 years ago
4 0
The following formula gives the connection between the force, the mass and the acceleration:
F=ma
In our case we know the force and the mass. F=20N and m=10kg
a=F/m
a=20m/s^2/10=2<span>m/s^2</span>
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ANSWER QUICK 40 POINTSSSS
cluponka [151]

Answer:

For 6 its D

For 7 its A

For 8 its C

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A car slows down from 27.7 m/s to 10.9 m/s in 2.37 s, what is the acceleration?
larisa [96]

Answer:

Answer. to final velocity 'v' =10.9 m/s in time 't' = 2.37 secs. So acceleration = -7.09 m/sec^2 or, decceleration is 7.09 m/sec^2

Explanation:

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Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c
kvv77 [185]

Answer:

B) electrons

Explanation:

When charge is transferred by friction, induction or conduction, the charge carriers are the electrons.

In fact, protons and neutrons are found within the nucleus of the atoms, so they are tightly bound and they cannot be easily gained/given off. On the contrary, electrons are found in the electron clouds around the nucleus, so atoms can more easily gain/lose electrons, which become free and can be passed by an object to another.

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3 years ago
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Why is it advisable to use a small value for the incidence angle when performing a glass prism experiment
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FOCAL LENGTH = 9.5cm i° e° d° 30 43 69 40 41 61 45 39 56 50 37 48 65 41 37 plot a graph of d° against i° from the graph Determine; (i) the minimum deviation and the corresponding angle of incidence (ii) the maximum deviation and the corresponding angle of incidence n=sin⁡(A+D÷2)÷(sinA÷2) Determine the error in n and explain why it is not advisable to use small values of i° in performing this experiment.
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4 years ago
Deer ticks can carry both Lyme disease and human granulocytic ehrlichiosis (HGE). In a study of ticks in the Midwest, it was fou
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Answer:

a)0.024

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Let 's represent the set of deer ticks Carrying Lyme disease with L and the set of deer ticks carrying Human Granulocytic Ehrlichiosis with H

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P(L) = 0.16

P(H) = 0.10

P(L n H) = 0.1 ·P( L u H )

Hence, P( L u H) = 10 ·P( L nH)

(a)

Hence. using the equation. P(L U H) = P(L) + P(H) - P(L n H)

Hence, 10 · P(L n H ) = 0.16 + 0.1 - P(L n H )

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(b)

We know that condition probability P(H ║ L) = p(L n H)/P(L)

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3 years ago
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