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3 years ago

The speed at which an object falls and the acceleration at which it falls are

Physics

1 answer:

allochka39001 [22]3 years ago

6 0

No, the speed at which an object falls is not equal to the acceleration at which it falls.

Answer:

Option B

Explanation:

Speed is defined as how fast an object can cover a specific distance and in what time it covers. So it is measured as the ratio of distance covered to the time taken to cover that distance. While acceleration is the rate of change of velocity. Moreover, speed is a scalar quantity and acceleration is a vector quantity. So most of the times, the direction will play an important role in the varying values of speed and acceleration. Also, acceleration of an object will depend upon the force and mass of the object. Thus, speed and acceleration will not attain same value always.

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Suppose that you are taking a course in geometry. You are trying to determine whether two geometric shapes are identical, so you

Nataly_w [17]

Explanation:

Yes, in order to determine whether two geometric figures are identical or not we tend to rotate one of the figure clockwise or anti clock wise mentally. However, in clockwise rotation larger the angel more will be the time taken for instance, it will take longer to rotate 120° than to rotate 40°. Whereas in anti clockwise ration it will be vice versa.

3 0

3 years ago

The current through a certain heater wire is found to be fairly independent of its temperature. If the current through the heate

bearhunter [10]

Answer:

Explanation:

the formular for the relationship between energy and current is E= I²Rt (Heat energy)

the heater is fairly independent of its temperature , and given the time to be constant.

with the current being doubled,

E = I² Rt

E/ I² = K

$\frac{E1}{I1^{2} }$ = $\frac{E2}{I2^{2} }$

E2 = $\frac{E1* I1^{2} }{I1^{2} }$

I2 = 2* I1

E2 = E1 * 4*I1² / I1²

dividing , we have that E2 = 4 * E1

which means during the same time interval the amount of energy will increase by a factor of four.

7 0

4 years ago

Where could you hear a sonic boom

ExtremeBDS [4]

Answer

A sonic boom is a continuous effect that occurs while the object is travelling at supersonic speeds.

7 0

4 years ago

The displacement at any given time of an object is x = 6 sin 98t , where the symbols have their usual meanings. i). Proof that t

Fofino [41]

A simple harmonic motion is defined by the amplitude and angular frequency of the oscillation, which are represented in the given function as 6 units and 98 rad/s respectively.

<h3>General wave equation for simple harmonic motion</h3>

y = A sinωt

where;

A is amplitude of the motion
ω is angular frequency

<h3>Amplitude of the oscillation</h3>

A = 6 units

<h3>Angular frequency of the wave</h3>

ω = 98 rad/s

A simple harmonic motion is defined by the amplitude and angular frequency of the oscillation. Thus, the wave is executing simple harmonic motion.

Learn more about simple harmonic motion here: brainly.com/question/17315536

#SPJ1

5 0

2 years ago

A car leaves an intersection traveling west. Its position 4 sec later is 21 ft from the intersection. At the same time, another

Alex_Xolod [135]

Answer:

15.8 ft/s

Explanation:

$\frac{da}{dt}$ = Velocity of car A = 9 ft/s

a = Distance car A travels = 21 ft

$\frac{db}{dt}$ = Velocity of car B = 13 ft/s

b = Distance car B travels = ft

c = Distance between A and B after 4 seconds = √(a²+b²) = √(21²+28²) = √1225 ft

From Pythagoras theorem

a²+b² = c²

Now, differentiating with respect to time

$2a\frac{da}{dt}+2b\frac{db}{dt}=2c\frac{dc}{dt}\\\Rightarrow a\frac{da}{dt}+b\frac{db}{dt}=c\frac{dc}{dt}\\\Rightarrow \frac{dc}{dt}=\frac{a\frac{da}{dt}+b\frac{db}{dt}}{c}\\\Rightarrow \frac{dc}{dt}=\frac{21\times 9+28\times 13}{\sqrt{1225}}\\\Rightarrow \frac{dc}{dt}=15.8\ ft/s$

∴ Rate at which distance between the cars is increasing three hours later is 15.8 ft/s

6 0

4 years ago