A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by
Paul has magnitude 48.0 N and direction 61.0∘ south of west. How much work does Paul’s force do during a displacement of the crate that is 12.0 m in the direction 22.0∘ east of north?
1 answer:
Answer:
-570.4 J
Explanation:
Parameters given:
Force = 48N, 61° SW
Displacement = 12m, 22.0 NE
Work done is given by:
W = F*d*cosθ
To find θ:
θ = 61 + 90 + 22 = 172°
=> W = 48 * 12 * cos172
W = - 570.4 J
Hence, the work to be done is - 570.4J.
This value is negative because the applied force is opposite the direction of the displacement.
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