Answer:
Weak intermolecular forces, low thermal energy. When an object such as liquid becomes a solid in form, this is sometimes caused by drop of heat, kinetic, energy in an object. And fast if there's weak molecular interaction.
Explanation:
Answer:
a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis
b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction
c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis
Explanation:
For this exercise we draw a Cartesian coordinate system in this system: East coincides with the positive part of the x-axis and North with the positive part of the y-axis.
a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis
b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction
c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis
In the attachment we can see the representation of the three vectors
Answer: 800 km/h
Explanation:
Use equation for average speed
V=S/t
where S is distance
t is time
S=4800Km
t=6h
---------
V=S/t
V=4800Km/6h=800 Km/h
The weight changes from place to place as the weight is a vector quantity as well as a dependent quantity. Therefore, weight seems to be varying but the inertia is not.
<u>Explanation:
</u>
The weight as already known well, is not a universal constant, whereas the mass is. As the weight is a product of mass of the body and the gravitational acceleration working on it, it varies as the factor of acceleration involved makes it a vector quantity.
And thus be dependent upon the direction too. Inertia of the body is an independent factor, on the other hand, an inherent property and so does not change.
Answer: 
Explanation:
let this sign be ∅ (titha in degrees)
let coefficient of friction of 0.200 be u
and i be current i= 1.41A
mass m=1.14g/cm m=0.0114g/m
To find the magnetic field from the north will be:
tan ∅= u
∅=
∅=11.3°
The direction:
i L*B cos(∅)= umg
divide both by iLcos(∅) to find B
B=
where m=
B= 
B= 
