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zheka24 [161]
3 years ago
12

A comet is traveling through space with a speed of 3.40 ✕ 104 m/s when it collides with an asteroid that was at rest. The comet

and the asteroid stick together during the collision process. The mass of the comet is 1.05 ✕ 1014 kg, and the mass of the asteroid is 7.05 ✕ 1020 kg.
a. What is the speed of the center of mass of the asteroid-comet system before the collision?
b. What is the speed of the system's center of mass after the collision?
Physics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

a) vcm = 5.06*10⁻³ m/s

b) vcm = 5.06*10⁻³ m/s

Explanation:

v₁ = 3.40*10⁴ m/s

v₂ = 0 m/s

m₁ = 1.05*10¹⁴ Kg

m₂ = 7.05*10²⁰ Kg

vcm initial = ?

vcm final = ?

a)  Before the collision

vcm = (m₁*v₁ + m₂*v₂) / (m₁ + m₂)

vcm = (1.05*10¹⁴ Kg*3.40*10⁴ m/s + 7.05*10²⁰ Kg*0 m/s) / (1.05*10¹⁴ Kg + 7.05*10²⁰ Kg)

vcm = 5.06*10⁻³ m/s

a)  After the collision

m₁*v₁ + m₂*v₂ = (m₁ + m₂)*vcm

⇒  vcm = (m₁*v₁ + m₂*v₂) / (m₁ + m₂)

vcm = (1.05*10¹⁴ Kg*3.40*10⁴ m/s + 7.05*10²⁰ Kg*0 m/s) / (1.05*10¹⁴ Kg + 7.05*10²⁰ Kg)

vcm = 5.06*10⁻³ m/s

The speed of the system's center of mass is the same value.

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Starting from rest, a 2-m-long pendulum swings from an angleof
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Assume the initial angle of the swing is 12.8 degree with respect to the vertical. We can calculate the vertical distance from this initial point to the lowest point by first calculate the vertical distance from this point the the pivot point:

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5 0
3 years ago
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