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madreJ [45]
3 years ago
6

NEED THE ANSWER ASAP PLEASE

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

X = -2

Step-by-step explanation:

Vertical lines go up and down.  That means the x value is constant and the y value changes.  We have an x value of -2

X = -2

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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Find the range of the following piecewise function.
mash [69]

Answer:

\huge\boxed{[-5;\ -2)\ \cup\ [3;\ 13)}

Step-by-step explanation:

The following piecewise functions are linear functions. The graph of any of them is a line segment.

We just need to calculate the value of the function at each end specified in the brace.

y=3x-2\ \text{if}\ -1\leq x

Substitute x =-1 and x = 0:

x=-1\\y=3(-1)-2=-3-2=-5\\\\x=0\\y=3(0)-2=0-2=-2

Range of this piece is [-5; -2)

y=2x+3\ \text{if}\ 0\leq x

Substitute x =0and x = 5:

x=0\\y=2(0)+3=0+3=3\\\\x=5\\y=2(5)+3=10+3=13

Range of this piece is [3; 13)

Therefore the range of the following piecewise function is:

[-5;\ -2)\ \cup\ [3;\ 13)

Look at the picture.

6 0
2 years ago
How would I simplify the equation 5u^6x^2+20wx/15x^4
Akimi4 [234]

Answer:

The simplified form is 5u^6x^2+\frac{4w x^{-3}}{3}

Step-by-step explanation:

To simplify the expression given to use, we need to reduce the given expression in its simplest form. There should not be any possibility for the further cancelling out of the division terms, if any.

Now the expression that is given to us is:

5u^6x^2+\frac{20wx}{15x^4}\\

Here we will simplify it, as follows:

5u^6x^2+\frac{20wx}{15x^4}\\=5u^6x^2+\frac{4w}{3x^3}\\=5u^6x^2+\frac{4w x^{-3}}{3}

So this is the required simplified form.

3 0
3 years ago
19. Jeremy mowed several lawns to earn money for camp. After he paid $17 for
Gekata [30.6K]

Answer:

17+75=?

Step-by-step explanation:

6 0
3 years ago
The triangles shown here are congruent
Readme [11.4K]

Answer:

use your brain

Step-by-step explanation:

3 0
3 years ago
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