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KatRina [158]
3 years ago
6

Help please Algebra 2 B

Mathematics
1 answer:
snow_lady [41]3 years ago
7 0
A horizontal asymptote will have an equation in the form y=a.
We see only one choice like this here. It is y=97.
So correct answer is y=97.
It means that carrying capacity of the New England forests will be 97, and shows what maximum amount of moose can live there.
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An escalator lifts people to the second floor of a building 25 feet above the first floor. The escalator rises at a 30 degree an
ch4aika [34]

9514 1404 393

Answer:

  50 ft

Step-by-step explanation:

The side lengths in a 30-60-90 triangle have the ratios 1 : √3 : 2. The longest side is 2 times the length of the shortest side.

In this geometry, that means the length of the escalator is 2 times its height, so is ...

  x = 2(25 ft)

  x = 50 ft . . . . . distance a person travels

7 0
3 years ago
Janelle expanded the expression as shown below.<br> What ERRORS did she make? Select three options.
Setler79 [48]

Answer:

I'm   probably wrong

A-C

Step-by-step explanation:

7 0
3 years ago
A bulletin board has an area of 1/ 12 yd and a length of 1/3 yard the bulletin board is divided into six equal sections right vi
gulaghasi [49]

Answer: The 6 sections has an area of 1/72 square yards

Step-by-step explanation:

Length= area / length

Length = 1/12 ÷ 1/3 = 1/12 × 3/1 = 1/4 yards

Since the width and length are different and the 6 squares must be arranged in a 2 × 3 pattern.

The long side is 1/3 yard

1/4 ÷ 2/1 = 1/4 × 1/2 = 1/8 yard

And the width is 1/3 ÷ 3/1 = 1/3 × 1/3 = 1/9 yard

The 6 sections are 1/8 × 1/9 and each one has an area of 1/8×1/9 = 1/72 square yard

8 0
3 years ago
Read 2 more answers
Is -9 &lt;, &gt;, or = to 0?
Lostsunrise [7]
-9<0
Because 9 is negative, it's value is less than 0
7 0
4 years ago
If tanA+cotA=2 then find the value of cosA​
aniked [119]

Answer:

cos A=

\frac{1}{ \sqrt{2} }

Step-by-step explanation:

We know,

cotA=

\frac{1}{ \tan(a) }

Substituting the value of cot A in the given equation, we get

\tan( a)  +  \frac{1}{ \tan(a) }  = 2

\frac{{ \tan }^{2} a + 1}{  \:  \tan(a)  }  = 2

{ \tan }^{2 \: } a \:  + 1 = 2 tan \: a

{ \tan }^{2} a - 2 \tan \: a + 1 = 0

( \tan \: a - 1) {}^{2 }  = 0

\tan \: a - 1 =  \sqrt{0}

\tan \: a = 1

\tan \: a \:  =  \tan \: 45

a = 45

\cos \: a =  \cos \: 45

\cos \: a =   \frac{1}{ \sqrt{2} }

4 0
3 years ago
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