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Allushta [10]
2 years ago
14

a pet store has 7 cats here are their weights 12, 12, 9, 16, 11, 11, 9 find the mean weighy of these cats ​

Mathematics
1 answer:
shusha [124]2 years ago
5 0

Answer:

The mean weight of the cats is 11.42 (rounded)

Step-by-step explanation:

To find the mean, you add up all the weights (12, 12, 9, 9, 11, 11, 16) and then divided the sum (80) of the weights by the number of cats (7)

12+12+9+9+11+11+16= 80

80 ÷ 7= 11.42857143 (I rounded my answer to 11.42)

I hope this was helpful. Have a wonderfull rest of your day!

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eimsori [14]
B

Explanation
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6 0
2 years ago
X^2+2x+1 is a perfect square trinomial <br><br> True of False?
Nimfa-mama [501]

Answer:

True.

Step-by-step explanation:

It is because it is in the form a^2x^2+2abx+b^2 and this equals (ax+b)^2.

Why it is in that form:  well comparing  a^2x^2+2abx+b^2, we have a=1, b=1. Testing, plug in those values:

(1)^2x^2+2(1)(1)x+(1)^2

1x^2+2x+1

x^2+2x+1.

This has the squared form of (x+1)^2.

Test if you like:

(x+1)^2

(x+1)(x+1)

Use foil to expand:

First: x(x)=x^2

Outer: x(1)=x

Inner: 1(x)=x

Last: 1(1)=1

---------------Add together

x^2+2x+1

It does indeed equal.

4 0
2 years ago
If the range of the function f(x) = 7x – 2.7 is {14.1, 30.9, 41.4, 58.9, 68}, what is its domain?
Drupady [299]

domain is {2.4, 4.8, 6.3, 8.8, 10.1 }

For domain, equate f(x) to each value in the range and solve for x

7x - 2.7 = 14.1 ⇒ x = \frac{x14.1 + 2.7}{7} = 2.4

7x - 2.7 = 30.9 ⇒ x = \frac{30.9 + 2.7}{7} = 4.8

7x - 2.7 = 41.4 ⇒ x = \frac{41.4 + 2.7}{7} = 6.3

7x - 2.7 = 58.9 ⇒ x = \frac{58.9 + 2.7}{7} = 8.8

7x - 2.7 = 68 ⇒ x = \frac{68 + 2.7}{7} = 10.1


7 0
3 years ago
Kyle has 105 baseball cards and must give 2/5 of his cards away.
klasskru [66]
1. 42 cards
2. 3/5 of his cards
5 0
3 years ago
The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2
Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in ^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15 ways.

The probability of getting two 3 as outcome is \frac{1}{4} \times\frac{1}{4} = \frac{1}{16}.

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is 1 - \frac{1}{4} = \frac{3}{4}.

Hence, the required probability is 15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}≅0.2966 or, 0.23.

4 0
3 years ago
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