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3 years ago

What is the surface area of a rectangle with the base 10 and the height 15

Mathematics

2 answers:

nikdorinn [45]3 years ago

4 0

The surface area is 150
the formula to solving the area of a rectangle is b*h=a
10*15 =150

Deffense [45]3 years ago

3 0

Answer:susuxusixoaos

Step-by-step explanation:

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3 years ago

A math test is worth 100 points and has 38 problems. each problem is worth either 5 points or 2 points. how many problems of eac

blondinia [14]

Hey there,
There are 2 ways
1st way:
Since there are 8 5 point problems, 38 - 8 = 30, will give you the 2 point problems.

2nd way:
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Hope this helps :))

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3 years ago

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Which fraction is equivalent to <br><br> 3/5

pentagon [3]

Answer:

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Step-by-step explanation:

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2 years ago

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Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

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