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Snowcat [4.5K]
3 years ago
6

L. What does it mean to "convert" from one unit to another? Give an example.

Physics
2 answers:
TiliK225 [7]3 years ago
5 0

These are four questions and four answers


Question 1. What does it mean to "convert" from one unit to another? Give an example.


Convert from one unit to another is transforming or changing the magnitude to an equivalent measure according to a different pattern of comparison or unit of measure.


For example, converting from meter to centimeters, means to transform the unit of measure (the pattern of comparison) from meter to centimeter.


When your measure is 3 meters, means the length is 3 times the standard pattern named meter.


Therefore, converting it to centimeters means that you want to know how many times is 3 meters relative to the a new pattern named centimeter.


Since, 1 meter equals 100 cm, you build a conversion factor which you can use to make the conversion:


1 m = 100 cm ⇒ 1 = 100 cm / 1 m


∴ 3 m = 3 m × 100 cm / 1 m = 300 cm.


Question 2. What are the general mathematical operations you use when converting from one SI unit to another?


The most common mathematical operations are the basic ones: addition, substraction, multiplication and division.


See one example of each one:


a) Addition:


Transform 20°C to K: 20 + 273.15 K = 293.15 K


b) Subtraction:


Convert 300 K to celsius degrees: 300 - 273.15°C = 26.85°C


c) Multiplication


Convert 1000 Km to meter


1000 Km × 1000 m/Km = 1,000,000 m


d) Division


Convert 1540 mm Hg to atm


1 atm = 760 mmHg ⇒ 1 = 760 mmHg / atm

1540 mmHg / (760 mmHg / atm) = 2.026 atm


Question 3. How many meters do you cover in a 10 km (10-K) race?


This requires to convert 10 km to the equivalent number of meters.


Conversion factor: 1 km = 1000 m ⇒ 1 = 1000 m/Km


∴ 10 Km = 10 Km × 1000 m/km = 10,000 m ← answer.


Quesiton 4. An Olympic swimming pool is 50 meters long. You swim from one end to the other four times.


a. How many meters do you swim?

4 laps × 50 m/lap = 200 m ← answer


b. How many kilometers do you swim?


1 = 1 km / 1000m

200 m = 200 × 1 km / 1000 m = 0.200 km ← answer


c. How many centimeters do you swim?


1 m = 100 cm ⇒ 1 = 100 cm / m

200 m = 200 m × 100 cm/m = 20,000 cm ← answer

ladessa [460]3 years ago
5 0
L. What does it mean to "convert" from one unit to another? Give an example.
To convert means is to obtain an equivalent value with a specific unit to another unit. An example would be <span>1 inch is equal to 2.54 cm.</span>

2. What are the general mathematical operations you use when converting from one SI unit to another? 
The mathematical operations used in converting units would be multiplication and division.

3. How many meters do you cover in a 10 km (10-K) race? 

4. An Olympic swimming pool is 50 meters long. You swim from one end to the other four times. 
a. How many meters do you swim? 
50 x 4 = 200 meters
b. How many kilometers do you swim? 
200 meters = 0.20 kilometers
c. How many centimeters do you swim? 
200 meters = 20000 centimeters
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A 0.54 kg air hockey puck is initially at rest. What will it's kinetic energy energy be after a net force of 0.56 N acts on it f
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Answer:

Kf = 470 mJ

Explanation:

  • According the work-energy theorem, the change in the kinetic energy of one object, is equal to the net work done on it.
  • Since the puck is initially at rest, the change is kinetic energy is just the final kinetic energy of the puck.
  • Assuming that the net force is horizontal, and causes a horizontal displacement also, we can find the net work on the puck as follows:

       W_{net} = F_{net} * \Delta X = 0.56 N * 0.84 m = 0.47 J = 470 mJ (1)

  • As we have already said, (1) is equal to the final kinetic energy of the puck:
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3 years ago
Church organs have a set of pipes with different lengths. With those different pipes organs can produce sounds over a wide range
Paraphin [41]

Answer: The shortest possible wavelength of sound the organ can produce is 0.224 m

Explanation:

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light

c = speed of light = 331m/s

As wavelength and frequency follows inverse relation, shortest wavelength is produced by highest frequency.

\nu = highest frequency of light = 1.48kHz=1.48\times 10^3Hz=1.48\times 10^3s^{-1}       1Hz=1s^{-1}

\lambda=\frac{331m/s}{1.48\times 10^3s^{-1}}=0.224m

Thus the shortest possible wavelength of sound the organ can produce is 0.224 m

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The difference between newtons first law of motion and newtons third law of motion
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The difference is two laws of motion.
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Una joven va en su bicicleta.Cuando llega a una esquina, se detiene a tomar aguade su cantimplora.En ese momento pasa su amigo e
Kruka [31]

Queremos encontrar y comparar dos ecuaciones de moviemiento para asi obtener distintos valores.

Las soluciones son:

a) 16.23s

b)  289.8m

Definamos el t = 0s al momento en el que la joven comienza a acelerar.

Encontremos su ecuación de movimiento.

Conocemos la aceleración, que es:

A(t) = 2.2m/s^2

Para obtener su velocidad debemos integrar sobre el tiempo, como ella estaba quieta, es decir no hay velocidad inicial, no tendremos constante de integración, asi obtenemos:

V(t) = (2.2m/s^2)*t

Para la posición integramos nuevamente, vamos a definir a la<u> posicion inicial (el lugar donde ella y su amigo se cruzan) como el cero de la posición,</u> así que acá tampoco tenemos constante de integración.

P(t) = (1/2)*(2.2m/s^2)*t^2 = (1.1 m/s^2)*t^2

Ahora busquemos la ecuación de su amigo.

El se mueve con velocidad constante de 8m/s, entonces tiene:

v(t) = 8m/s

Para obtener su posición integramos:

p(t) = (8m/s)*t + p

Donde p es la distancia que el recorre en los 20 segundos que pasan entre que pasa a su amiga y su amiga comienza a acelerar.

p = (8m/s)*20s = 160m

p(t) = (8m/s)*t + 160m

a) La joven alcanzara a su amigo cuando las dos <u>ecuaciones de posicion sean iguales</u>:

P(t) = p(t)

(1.1 m/s^2)*t^2 = (8m/s)*t + 160m

Podemos reescribir lo de arriba como:

(1.1 m/s^2)*t^2 - (8m/s)*t - 160m = 0

Esto es una ecuación cuadratica, para encontrar las soluciones tenemos que usar la formula de Bhaskara:

t = \frac{-(-8m/s) \pm\sqrt{ (-8m/s)^2 - 4*(-160m)*(1.1 m/s^2)} }{2*(1.1 m/s^2)} \\\\t = \frac{(8m/s) \pm 27.7 m/s}{2.2 m/s^2}

Solo nos interesa la solución positiva (pues la negativa no tiene sentido fisico) asi que tomamos:

t = \frac{(8m/s) + 27.7 m/s}{2.2 m/s^2} = 16.23s

Es decir, ella tarda 16.23 segundos en alcanzar a su amigo.

b) Para encontrar la distancia solo debemos evaluar su ecuación de movimiento en el tiempo que encontramos arriba:

P(16.23s) = (1.1 m/s^2)*(16.23s)^2 = 289.8m

Es decir, ella recorre 289.8m antes de alcanza a su amigo.

Si quieres aprender más puedes leer:

brainly.com/question/17123407

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The Northern and Southern Hemispheres face the sun evenly. What do the hemispheres experience at that time?(1 point)
Arturiano [62]

Answer:Ans.: The Southern Hemisphere experience Winter and Summer Solstice in different times than that of the Northern Hemisphere because: When the North Pole is tilted towards the Sun, the Northern Hemisphere experiences Summer Solstice. ... These conditions are reversed when the South hemisphere is tilted towards the Sun.

Explanation:

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