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Answer:
D. Axial stress divided by axial strain
Explanation:
Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
E= Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
The option D is correct.
Answer:
Explanation:
If Tim jogs a distance of 7.2 km to the west and then he turns south and jogs 1.4 km, the resultant displacement of Tim is calculated using the pythagoras theorem as shown;
R² = 7.2²+1.4²
R² = 51.84+1.96
R² = 53.8
R = √53.8
R = 7.33 km
Hence the resultant of Tim's jog back to the beginning is 7.33km
Answer: Water fills the bucket until its force/weight is greater than the block’s. The lever tilts over, causing the bucket to water the plant.
y = 0m
y0 = 166m
v0y = 0 m/s
g = 9.8 m/s^2
t = ?
Solve for t:
y = y0 + v0y*t - (0.5)gt^2
0 = 166 - (0.5)(9.8)t^2
t = 5.82 s
Now, using time, we can solve for the range using the equation:
x = vx(t)
x = (40)(5.82)
x = 232.8 m
The impact horizontal component of velocity will be 40 m/s as velocity in terms of x is always constant. To find the impact vertical component of velocity, we use the equation:
v = v0y - gt
v = 0 - (9.8)(5.82)
v = -57.04 m/s