A dragster and driver together have mass 942.9 kg . The dragster, starting from rest, attains a speed of 26.3 m/s in 0.61 s. Fin
1 answer:
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Answer:
Change in mechanical energy = work done by friction
so it is equal to
Explanation:
As we know that change in mechanical energy must be equal to the work done by non conservative forces only
So here when block moves down the inclined plane then the work done by friction force is given as
here we have
here we know that
so we have
Now the friction force on the block is given as
now work done by the friction is given as
Answer:
Given that
m = 5.3 kg
Fx = 2x + 4
We know that work done by force F given as
w= ∫ F. dx
a)
Given that x=1.08 m to x=6.5 m
Fx = 2x + 4
w= ∫ F. dx
w=62.7 J
b)
We know that potential energy given as
∫ dU = -∫F.dx ( w= ∫ F. dx)
ΔU= -62.7 J
c)
We know that form work power energy theorem
Net work = Change in kinetic energy
W= KE₂ - KE₁
62.7 =KE₂ - (1/2)x 5.3 x 3²
KE₂ = 86.55 J
This is the kinetic energy at 6.5m