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Snowcat [4.5K]
2 years ago
13

A dragster and driver together have mass 942.9 kg . The dragster, starting from rest, attains a speed of 26.3 m/s in 0.61 s. Fin

d the average acceleration of the dragster during this time interval. Answer in units of m/s 2 . lawson (al52364) – forces – szymczak – (41202) 4 032 (part 2 of 3) 10.0 points What is the size of the average force on the dragster during this time interval? Answer in units of N.
Physics
1 answer:
pshichka [43]2 years ago
5 0

Answer:

a) a = 43.11m/s^2

b) F = 40648.42N

Explanation:

We will use kinematics to calculate the average acceleration:

a = \frac{Vf-Vo}{t}

a = \frac{26.3-0}{0.61}

a = 43.11m/s^2

By dynamics:

F = m*a

F = 942.9*43.11

F = 40648.42N

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Name two types of sound wave​
kiruha [24]

Explanation:

two types of sound wave

  1. transverse wave
  2. Longitudinal wave
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3 years ago
a car travels from station A to B at 30kmph during its return trip A it travels 30 km pH for the first half distance and it 70 k
8_murik_8 [283]

Explanation:

If you cannot visualize it, just assume that the distance from station A to B is 420km. Each half is 210km.

When the car travels from A to B, it takes 420/30 = 14 hours.

When the car travels from B to the halfway point, it takes 210/30 = 7 hours.

When the car travels from the halfway point to A, it takes 210/70 = 3 hours.

Total time taken = 14 + 7 + 3 = 24 hours.

Total distance = 420km * 2 = 840km.

Hence, the average speed of the car is 840/24 = 35km/h.

3 0
3 years ago
4. A car accelerates, from rest, at 2.4 m/s?. How fast is the car traveling
pantera1 [17]

Answer:

19.2m/s

Explanation:

Assuming that 2.4m/s^2 was the acceleration and not a typo, we can use the equation v=at, where v=velocity, a=acceleration, and t=time,

plug in known varibles,

v=2.4*8

v=19.2m/s

4 0
2 years ago
If a fuse melts, does it create an open circuit, a closed circuit, or a short circuit?
Andrew [12]

Answer:

short circuit

7 0
3 years ago
Read 2 more answers
(c) A moving train has a kinetic energy of 8.1 x 10(power of 6)J.
tamaranim1 [39]

the friction force provided by the brakes is 30000 N.

<h3>What is friction force?</h3>

Friction force is the force that opposes the motion between two bodies in contact.

To calculate the average friction force provided by the brakes, we apply the formula below.

Formula:

  • K.E = F'd............. Equation 1

Where:

  • K.E = Kinetic energy of the train
  • F' = Friction force provided by the brakes
  • d = distance

Make F' the subject of the equation

  • F' = K.E/d............ Equation 2

From the question,

Given:

  • K.E = 8.1×10⁶
  • d = 270 m

Substitute these values into equation 2

  • F' = (8.1 ×10⁶)/270
  • F' = 30000 N

Hence, the friction force provided by the brakes is 30000 N

Learn more about friction force here: brainly.com/question/13680415

8 0
2 years ago
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